Fluid Pressure - Revision history

Ellen References at 10:44, 20 November 2019

2019-11-20T10:44:12Z

Ellen References at 16:16, 15 November 2019

2019-11-15T16:16:13Z

NRJC at 13:40, 7 June 2019

2019-06-07T13:40:25Z

NRJC at 12:52, 8 April 2019

2019-04-08T12:52:08Z

NRJC: /* Calculating Pressure in a Fluid */

2019-02-11T14:26:54Z

‎Calculating Pressure in a Fluid

NRJC at 14:26, 11 February 2019

2019-02-11T14:26:29Z

NRJC: /* Equation */

2019-02-11T14:06:14Z

‎Equation

NRJC at 14:05, 11 February 2019

2019-02-11T14:05:07Z

NRJC: Created page with "==Key Stage 4== ===Meaning=== Fluid Pressure is the force per unit area on a surface due to particles colliding with that surface. ===About Fluid Pres..."

2019-02-11T14:03:57Z

Created page with "==Key Stage 4== ===Meaning=== Fluid Pressure is the force per unit area on a surface due to particles colliding with that surface. ===About Fluid Pres..."

New page

==Key Stage 4==
===Meaning===
[[Fluid Pressure]] is the [[force]] per unit area on a surface due to [[particle]]s [[collide|colliding]] with that surface.

===About Fluid Pressure===
: The [[force]] responsible for [[pressure]] in a [[fluid]] is the [[weight]] of all the [[particle]]s above the [[object]].
: The [[pressure]] in a [[fluid]] decreases with height and increases with depth. The deeper into a [[fluid]] the greater the pressure.
: Since [[pressure]] increases with depth then the bottom of an [[object]] will experience more [[pressure]] than the top of the [[object]]. This causes a [[force]] called [[upthrust]].

===Equation===
Pressure = (Density of the Fluid) x (Gravitational Field Strength) x (Depth in the fluid)

<math> P = \rho g h</math>

Where:

<math> P</math> = [[Pressure]] at that depth.

<math> \rho</math> = [[Density]] of the [[fluid]]

<math> g </math> = [[Gravitational Field Strength]]

<math>h</math> = [[Depth]] in the [[fluid]]

← Older revision		Revision as of 10:44, 20 November 2019
Line 94:		Line 94:
	:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Fluid pressure, pages 169-171, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Fluid pressure, pages 169-171, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']
	:[https://www.amazon.co.uk/gp/product/178294558X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=178294558X&linkCode=as2&tag=nrjc-21&linkId=f0dfb66dafcb0c6e9449e7b1a4ae1ac175 ''Fluid pressure, pages 58, 59, GCSE Physics; The Revision Guide, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/178294558X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=178294558X&linkCode=as2&tag=nrjc-21&linkId=f0dfb66dafcb0c6e9449e7b1a4ae1ac175 ''Fluid pressure, pages 58, 59, GCSE Physics; The Revision Guide, CGP, AQA '']
		+
		+	====Edexcel====
		+
		+	:[https://www.amazon.co.uk/gp/product/1782948163/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948163&linkCode=as2&tag=nrjc-21&linkId=0fdbfd5dd397d6e24a9dfb250f08587f ''Fluid pressure, pages 318, 319, GCSE Physics, CGP, Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1292120223/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120223&linkCode=as2&tag=nrjc-21&linkId=068ecf40278c32406a7f1c6e66751417 ''Fluids and pressure, pages 202-203, GCSE Physics, Pearson Edexcel '']

← Older revision		Revision as of 16:16, 15 November 2019
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	<math> P \approx 390Pa</math>		<math> P \approx 390Pa</math>
	\|}		\|}
		+
		+	===References===
		+	====AQA====
		+
		+	:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Fluid pressure, pages 169-171, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/178294558X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=178294558X&linkCode=as2&tag=nrjc-21&linkId=f0dfb66dafcb0c6e9449e7b1a4ae1ac175 ''Fluid pressure, pages 58, 59, GCSE Physics; The Revision Guide, CGP, AQA '']

@@ Line 71: / Line 71: @@
 <math> P = 6468Pa</math>
-Since the [[miner]] also has normal atmospheric pressure 101kPa is added.
+Since the miner also has normal atmospheric pressure 101kPa is added.
 <math> P_{Total} = 6468 + 101000</math>

← Older revision		Revision as of 14:26, 11 February 2019
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	<math> P_{Total} = 6468 + 101000</math>		<math> P_{Total} = 6468 + 101000</math>
−

	<math> P_{Total} = 107468Pa</math>		<math> P_{Total} = 107468Pa</math>

← Older revision		Revision as of 14:26, 11 February 2019
Line 24:		Line 24:

	<math>h</math> = [[Depth]] in the [[fluid]]		<math>h</math> = [[Depth]] in the [[fluid]]
		+
		+	===Calculating Pressure in a Fluid===
		+	{\| class="wikitable"
		+	\| style="height:20px; width:200px; text-align:center;" \|A whale dives to a depth of 1300m below sea level. Given the density of [[water]] is 1000kg/m<sup>3</sup>, calculate the [[pressure]] on the whale due to the water correct to two [[Significant Figures\|significant figures]].
		+	\| style="height:20px; width:200px; text-align:center;" \|Normal atmospheric pressure at sea level is 101kPa. A miner works in a mine shaft 550m below the surface of the Earth. Given the density of the [[Earth's Atmosphere\|atmosphere]] at this level is 1.2kg/m<sup>3</sup>, calculate the [[pressure]] on the miner correct to two [[Significant Figures\|significant figures]].
		+	\| style="height:20px; width:200px; text-align:center;" \|A piece of [[Lithium]] is submersed 4.3cm deep in oil prevent it from oxidising. The oil has a [[density]] of 932kg/m<sup>3</sup>, calculate the [[pressure]] on the [[Lithium]] due to the oil correct to two [[Significant Figures\|significant figures]].
		+	\|-
		+	\| style="height:20px; width:200px; text-align:left;" \|'''1. State the known quantities'''
		+
		+	[[Density]] = 1000kg/m<sup>3</sup>
		+
		+	[[Gravitational Field Strength]] = 9.8N/kg
		+
		+	[[Depth]] = 1300
		+	\| style="height:20px; width:200px; text-align:left;" \|'''1. State the known quantities'''
		+
		+	[[Density]] = 1.2kg/m<sup>3</sup>
		+
		+	[[Gravitational Field Strength]] = 9.8N/kg
		+
		+	[[Depth]] = 550m
		+	\| style="height:20px; width:200px; text-align:left;" \|'''1. State the known quantities'''
		+
		+	[[Density]] = 932kg/m<sup>3</sup>
		+
		+	[[Gravitational Field Strength]] = 9.8N/kg
		+
		+	[[Depth]] = 4.3cm = 0.043m
		+	\|-
		+	\| style="height:20px; width:200px; text-align:left;" \|'''2. [[Substitute (Maths)\|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)\|solve]].'''
		+
		+	<math> P = \rho g h</math>
		+
		+	<math> P = 1000 \times 9.8 \times 1300</math>
		+
		+	<math> P = 12740000Pa</math>
		+
		+	<math> P \approx 13000000Pa</math>
		+
		+	\| style="height:20px; width:200px; text-align:left;" \|'''2. [[Substitute (Maths)\|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)\|solve]].'''
		+
		+	<math> P = \rho g h</math>
		+
		+	<math> P = 1.2 \times 9.8 \times 550</math>
		+
		+	<math> P = 6468Pa</math>
		+
		+	Since the [[miner]] also has normal atmospheric pressure 101kPa is added.
		+
		+	<math> P_{Total} = 6468 + 101000</math>
		+
		+
		+	<math> P_{Total} = 107468Pa</math>
		+
		+	<math> P_{Total} \approx 110000Pa</math>
		+	\| style="height:20px; width:200px; text-align:left;" \|'''2. [[Substitute (Maths)\|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)\|solve]].'''
		+
		+	<math> P = \rho g h</math>
		+
		+	<math> P = 932 \times 9.8 \times 0.043</math>
		+
		+	<math> P = 392.7448Pa</math>
		+
		+	<math> P \approx 390Pa</math>
		+	\|}

@@ Line 15: / Line 15: @@
 <math> P = \rho g h</math>
-Where:
+Where
 <math> P</math> = [[Pressure]] at that depth.

← Older revision		Revision as of 14:06, 11 February 2019
Line 9:		Line 9:

	===Equation===		===Equation===
		+	''NB: You do not need to remember this equation.''
		+
	Pressure = (Density of the Fluid) x (Gravitational Field Strength) x (Depth in the fluid)		Pressure = (Density of the Fluid) x (Gravitational Field Strength) x (Depth in the fluid)

@@ Line 17: / Line 17: @@
 <math> P</math> = [[Pressure]] at that depth.
-<math> \rho</math> = [[Density]] of the [[fluid]]
+<math> \rho</math> = [[Density]] of the [[fluid]] (This symbol is a 'rho' not a 'p')
 <math>  g </math> = [[Gravitational Field Strength]]
 <math>h</math> = [[Depth]] in the [[fluid]]