Newton's Second Law - Revision history

Ellen References at 16:16, 23 November 2019

2019-11-23T16:16:48Z

Ellen References at 13:16, 10 November 2019

2019-11-10T13:16:14Z

NRJC: /* Equation */

2019-06-07T13:42:06Z

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2019-06-07T13:41:57Z

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2019-02-14T17:12:24Z

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NRJC: /* Example Calculations */

2019-02-14T17:02:27Z

‎Example Calculations

NRJC at 16:51, 14 February 2019

2019-02-14T16:51:54Z

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NRJC: /* =Finding the Force given Mass and Acceleration */

2019-02-14T16:50:32Z

‎=Finding the Force given Mass and Acceleration

NRJC: Created page with "==Key Stage 4 Foundation== ===Meaning=== '''Newton's Second Law''' states that "Force = Mass x Acceleration, which means the acceleration of an object is Directly Pr..."

2019-02-14T16:50:00Z

Created page with "==Key Stage 4 Foundation== ===Meaning=== '''Newton's Second Law''' states that "Force = Mass x Acceleration, which means the acceleration of an object is Directly Pr..."

New page

==Key Stage 4 Foundation==
===Meaning===
'''Newton's Second Law''' states that "Force = Mass x Acceleration, which means the [[acceleration]] of an [[object]] is [[Directly Proportional|directly proportional]] to the [[Resultant Force|resultant force]] acting upon it."

===About Newton's Second Law===
: '''Newton's Second Law''' can be used to calculate the [[acceleration]] of an [[object]] given its [[mass]] and the [[Resultant Force|resultant force]] acting upon it.

===Equation===
Force = Mass x Acceleration

<math>F=ma</math>

Where:

F = The [[Resultant Force]] on the [[object]].

m = The [[mass]] of the [[object]].

a = The [[acceleration]] of the [[object]].

===Example Calculations===
====Finding the Force given Mass and Acceleration===
{| class="wikitable"
| style="height:20px; width:200px; text-align:center;" |A 2.3kg [[object]] [[accelerate]]s at a rate of 8.8m/s/s. Calculate the [[Resultant Force|resultant force]] acting on the [[object]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:200px; text-align:center;" |A 5.5x104kg rocket [[accelerate]]s at a rate of 61m/s/s. Calculate the [[Resultant Force|resultant force]] acting on the rocket correct to two [[Significant Figures|significant figures]].
|-
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 2.3kg

a = 8.8m/s/s
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 5.5x104kg

a = 61m/s/s
|-
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''

<math>F=ma</math>

<math>F=2.3 \times 8.8</math>

<math>F=20.24N</math>

<math>F \approx 20N</math>
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''

<math>F=ma</math>

<math>F=5.5 \times 10^4 \times 61</math>

<math>F=3355000N</math>

<math>F \approx 3.4 \times 10^6 N</math>
|}

====Finding the Acceleration given Mass and Force===
{| class="wikitable"
| style="height:20px; width:200px; text-align:center;" |A 7kg [[object]] is subjected to a [[Resultant Force|resultant force]] of 53N. Calculate the [[acceleration]] of the [[object]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:200px; text-align:center;" |A 160g snooker ball experiences a [[Resultant Force|resultant force]] of 12N. Calculate the [[acceleration]] of the snooker ball correct to two [[Significant Figures|significant figures]].
|-
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 7kg

F = 53N
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 160g = 0.16kg

F = 12N
|-
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''

<math>F=ma</math>

<math>53=7a</math>
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''

<math>F=ma</math>

<math>12=0.16a</math>
|-
| style="height:20px; width:200px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>a = \frac{53}{7}</math>

<math>a = 7.571m/s/s</math>

<math>a \approx 7.6m/s/s</math>
| style="height:20px; width:200px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>a = \frac{12}{0.16}</math>

<math>a = 75m/s/s</math>
|}

==Key Stage 4 Higher==
===Meaning===
'''Newton's Second Law''' states that "Force = Mass x Acceleration, which means the [[acceleration]] of an [[object]] is [[Directly Proportional|directly proportional]] to the [[Resultant Force|resultant force]] acting upon it."

===About Newton's Second Law===
: '''Newton's Second Law''' can be used to calculate the [[acceleration]] of an [[object]] given its [[mass]] and the [[Resultant Force|resultant force]] acting upon it.
: '''Newton's Second Law''' provides a definition for [[Inertial Mass|inertial mass]] as the [[ratio]] of [[force]] to the [[acceleration]] of an [[object]] <math>m= \frac{F}{a}</math>.

===Equation===
Force = (Inertial Mass) x Acceleration

<math>F=ma</math>

Where:

F = The [[Resultant Force]] on the [[object]].

m = The [[Inertial Mass]] of the [[object]].

a = The [[acceleration]] of the [[object]].

===Example Calculations===
====Finding the Force given Mass and Acceleration===
{| class="wikitable"
| style="height:20px; width:200px; text-align:center;" |A 1.23Mg [[object]] [[accelerate]]s at a rate of 5.3x10-2m/s/s. Calculate the [[Resultant Force|resultant force]] acting on the [[object]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:200px; text-align:center;" |A 1.7x10ng cell [[accelerate]]s at a rate of 320m/s/s. Calculate the [[Resultant Force|resultant force]] acting on the rocket correct to two [[Significant Figures|significant figures]].
|-
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 1.23Mg = 1230kg

a = 5.3x10-2m/s/s
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 1.7ng = 1.7x10-12kg

a = 320m/s/s.
|-
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''

<math>F=ma</math>

<math>F=1230 \times 5.3 \times 10^{-2}</math>

<math>F=65.19</math>

<math>F \approx 65N</math>
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''

<math>F=ma</math>

<math>F=1.7 \times 10^{-12} \times 320</math>

<math>F=0.000000000544N</math>

<math>F \approx 5.4 \times 10^{-10}N</math>
|}

====Finding the Acceleration given Mass and Force===
{| class="wikitable"
| style="height:20px; width:200px; text-align:center;" |A 9.2g [[object]] is subjected to a [[Resultant Force|resultant force]] of 3.7kN. Calculate the [[acceleration]] of the [[object]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:200px; text-align:center;" |A 333 tonne passenger plane experiences a [[Resultant Force|resultant force]] of 1.008MN. Calculate the [[acceleration]] of the passenger plane correct to two [[Significant Figures|significant figures]].
|-
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 9.2g = 0.0092kg

F = 3.7kN = 3700N
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''

m = 333 tonne = 3.33 x 105kg

F = 1.008MN = 1.008 x 106N
|-
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''

<math>F=ma</math>

<math>3700=0.0092a</math>
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''

<math>F=ma</math>

<math>1.008 \times 10^6 = (3.33 \times 10^5 )a</math>
|-
| style="height:20px; width:200px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>a = \frac{3700}{0.0092}</math>

<math>a = 402173.913m/s/s</math>

<math>a \approx 4.0 \times 10^5m/s/s</math>
| style="height:20px; width:200px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>a = \frac{1.008 \times 10^6}{3.33 \times 10^5}</math>

<math>a = 3.027m/s/s</math>

<math>a \approx 3.0m/s/s</math>
|}

← Older revision		Revision as of 16:16, 23 November 2019
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	:[https://www.amazon.co.uk/gp/product/1782946403/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782946403&linkCode=as2&tag=nrjc-21&linkId=32a0abb60dff015b15b50e9b1d7b4644 ''Newton’s Second Law; investigating, pages 167, 168, GCSE Combined Science Trilogy; Physics, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/1782946403/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782946403&linkCode=as2&tag=nrjc-21&linkId=32a0abb60dff015b15b50e9b1d7b4644 ''Newton’s Second Law; investigating, pages 167, 168, GCSE Combined Science Trilogy; Physics, CGP, AQA '']
	:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Newton’s Second Law; investigating, pages 199, 200, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']		:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Newton’s Second Law; investigating, pages 199, 200, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']
		+
		+	====Edexcel====
		+
		+	:[https://www.amazon.co.uk/gp/product/1782945741/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945741&linkCode=as2&tag=nrjc-21&linkId=30da4f2178da182547b62a7329d13b57 ''Newton’s Second Law, pages 149, 151, 154, GCSE Combined Science; The Revision Guide, CGP, Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1782945733/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945733&linkCode=as2&tag=nrjc-21&linkId=2a2dbec9db6bf5766c0458d908fa0a52 ''Newton’s Second Law, pages 16, 18, 21, GCSE Physics; The Revision Guide, CGP, Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1292120223/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120223&linkCode=as2&tag=nrjc-21&linkId=068ecf40278c32406a7f1c6e66751417 ''Newton’s Second Law, pages 18-19, GCSE Physics, Pearson Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1292120193/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120193&linkCode=as2&tag=nrjc-21&linkId=572df39392fb4200db8391d98ae6314e ''Newton’s Second Law, pages 302-303, GCSE Combined Science, Pearson Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1782948163/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948163&linkCode=as2&tag=nrjc-21&linkId=0fdbfd5dd397d6e24a9dfb250f08587f ''Newton’s Second Law, pages 35, 36, 46, GCSE Physics, CGP, Edexcel '']
		+	:[https://www.amazon.co.uk/gp/product/1782948163/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948163&linkCode=as2&tag=nrjc-21&linkId=0fdbfd5dd397d6e24a9dfb250f08587f ''Newton’s Second Law; investigating, pages 39, 40, GCSE Physics, CGP, Edexcel '']

← Older revision		Revision as of 13:16, 10 November 2019
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	<math>m \approx 1400kg</math>		<math>m \approx 1400kg</math>
	\|}		\|}
		+
		+	===References===
		+	====AQA====
		+
		+	:[https://www.amazon.co.uk/gp/product/019835939X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=019835939X&linkCode=as2&tag=nrjc-21&linkId=57e96876985fc39b1a3d8a3e3dc238b6 ''Newton’s Second Law of motion, pages 144-145, GCSE Physics; Third Edition, Oxford University Press, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782946403/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782946403&linkCode=as2&tag=nrjc-21&linkId=32a0abb60dff015b15b50e9b1d7b4644 ''Newton’s Second Law, pages 164, 165, GCSE Combined Science Trilogy; Physics, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Newton’s Second Law, pages 196, 197, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945598/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945598&linkCode=as2&tag=nrjc-21&linkId=ad276ad49df77ab4b40ab4fd0fe10102 ''Newton’s Second Law, pages 212, 214, GCSE Combined Science; The Revision Guide, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945598/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945598&linkCode=as2&tag=nrjc-21&linkId=ad276ad49df77ab4b40ab4fd0fe10103 ''Newton’s Second Law; investigating, page 214, GCSE Combined Science; The Revision Guide, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782946403/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782946403&linkCode=as2&tag=nrjc-21&linkId=32a0abb60dff015b15b50e9b1d7b4644 ''Newton’s Second Law; investigating, pages 167, 168, GCSE Combined Science Trilogy; Physics, CGP, AQA '']
		+	:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Newton’s Second Law; investigating, pages 199, 200, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']

@@ Line 108: / Line 108: @@
 <math>F=ma</math>
-Where:
+Where
 <math>F</math> = The [[Resultant Force]] on the [[object]].

@@ Line 11: / Line 11: @@
 <math>F=ma</math>
-Where:
+Where
 <math>F</math> = The [[Resultant Force]] on the [[object]].

@@ Line 117: / Line 117: @@
 ===Example Calculations===
-====Finding the Force given Mass and Acceleration====
+====Finding the Force given Inertial Mass and Acceleration====
 {| class="wikitable"
 | style="height:20px; width:300px; text-align:center;" |A 1.23Mg [[object]] [[accelerate]]s at a rate of 5.3x10<sup>-2</sup>m/s/s. Calculate the [[Resultant Force|resultant force]] acting on the [[object]] correct to two [[Significant Figures|significant figures]].
@@ Line 153: / Line 153: @@
 |}
-====Finding the Acceleration given Mass and Force====
+====Finding the Acceleration given Inertial Mass and Force====
 {| class="wikitable"
 | style="height:20px; width:300px; text-align:center;" |A 9.2g [[object]] is subjected to a [[Resultant Force|resultant force]] of 3.7kN. Calculate the [[acceleration]] of the [[object]] correct to two [[Significant Figures|significant figures]].
@@ Line 192: / Line 192: @@
 <math>a \approx 3.0m/s/s</math>
 |}

@@ Line 110: / Line 110: @@
 Where:
-F = The [[Resultant Force]] on the [[object]].
+<math>F</math> = The [[Resultant Force]] on the [[object]].
-m = The [[Inertial Mass]] of the [[object]].
+<math>m</math> = The [[Inertial Mass]] of the [[object]].
-a = The [[acceleration]] of the [[object]].
+<math>a</math> = The [[acceleration]] of the [[object]].
 ===Example Calculations===