Changes

: <math>5km = 5x1000m 5 \times 1000m = 5000m</math>: <math>12kA = 12x1000A 12\times1000A = 12000A</math>: <math>3.4kV = 3.4x1000V 4\times1000V = 3400V</math>: <math>0.53kN = 0.53x1000N 53\times1000N = 530N</math> : <math>0.082kJ = 0.082x1000J 082\times1000J = 82J</math>

: <math>23000m = (\frac{23000/}{1000)}km = 23km</math> : <math>8200A = (\frac{8200/}{1000)}kA = 8.2kA</math> : <math>670V = (\frac{670/}{1000)}kV = 0.67kV</math> : <math>32N = (\frac{32/}{1000)}kN = 0.032kN</math>: <math>2J = (\frac{2/}{1000)}kJ = 0.002kJ</math>

To convert from [[kilo]] to the base unit you must times by 1000.: 5km = 5x1010³m . <math>5km = 5 \times 10^3m = 5000m</math> : <math>12kA = 12x1012\times 10^3A = 12000A<sup/math>3 </supmath>A = 12000A: 3.4kV = 3.4x104\times 10^3V = 3400V<sup/math>3 </supmath>V = 3400V: 0.53kN = 0.53x1053\times 10^3N = 530N<sup/math>3 </supmath>N = 530N: 0.082kJ = 0.082x10<sup>3082\times 10^3J = 82J</supmath>J = 82J

To convert to [[kilo]] from a base unit you must divide by 1000.: 23000m = (23000/10³). <math>23000m = \frac{23000}{10^3}km = 23km</math> : <math>8200A = (\frac{8200/}{10^{^3})}kA = 8.2kA</math>: <math>670V = (\frac{670/}{10^{^3})}kV = 0.67kV</math>: <math>32N = (\frac{32/}{10^{^3})}kN = 0.032kN</math>: <math>2J = (\frac{2/}{10^{^3})}kJ = 0.002kJ</math>