20,345
edits
Changes
→Calculating Atomic Number
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>Q_{proton} Q = 1\times1.60\times10^{-19}</math>[[Coulomb|C]]
<math>m_{proton} m = 1\times1.67\times10^{-27}</math>[[Kilogram|kg]]
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
The [[Electrical Charge|charge]] on an [[Magnesium|Mg]] 2+ [[ion]] is 2 x [[Elementary Charge|elementary charge]].
<math>Q_{Mg2+} Q = 2\times1.60\times10^{-19}</math>[[Coulomb|C]]
The [[mass]] of [[Magnesium|Magnesium-24]] 2+ [[ion]] is the mass of 24 [[nucleon]]s + 10 [[electron]]s.
<math>m_{Mg24} m = (24\times1.67\times10^{-27} + 10\times9.11\times10^{-31})</math>[[Kilogram|kg]]
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
====Calculating Mass====
{| class="wikitable"
| style="height:20px; width:300px; text-align:center;" |Calculate the [[mass]] of an [[ion]] with an a [[Electrical Charge|charge]] of -3.20x10<sup>-19</sup>[[Coulomb|C]] and a '''specific charge''' of -5.80x10<sup>6</sup>Ckg<sup>-1</sup>.
| style="height:20px; width:300px; text-align:center;" |Calculate the [[Relative Atomic Mass|relative atomic mass]] of a [[Atomic Nucleus|nucleus]] with an [[Electrical Charge|charge]] of 9.61x10<sup>-19</sup>[[Coulomb|C]] and a '''specific charge''' of 4.11x10<sup>7</sup>Ckg<sup>-1</sup>.
|-
{| class="wikitable"
| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[neutron]]s in an [[isotope]] of [[Titanium]] with a [[Atomic Nucleus|nucleus]] of '''specific charge''' 4.58x10<sup>7</sup>Ckg<sup>-1</sup>.
| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[neutron]]s in an [[isotope]] of [[Neon]] with the '''specific charge''' of -2....... 46x10<sup>6</sup>Ckg<sup>-1</sup> for a [[NeonSelenium|Neon Selenium 2-]] [[ion]].
|-
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>S.C. = -2.46\times10^{6}</math>Ckg<sup>-1</sup>
A 2- [[ion]] has two more [[electron]]s than [[proton]]s giving it a [[Negative Charge|negative charge]].
<math>Q = -2\times1.60\times10^{-19}</math>C
<math>m = (z + n)\times1.67\times10^{-27}+(z+2)\times9.11\times10^{-31}</math>kg
Where z is the number of [[proton]]s, n is the number of [[neutron]]s, (z+n) is the [[Relative Atomic Mass|relative atomic mass]] and (z+2) is the number of [[electron]]s since there are two more [[electron]]s than [[proton]]s.
Therefore
<math>m = (34 + n)\times1.67\times10^{-27}+36\times9.11\times10^{-31}</math>kg
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>S.C. = \frac{Q}{m}</math>
<math>-2.46\times10^{6} = \frac{-2\times1.60\times10^{-19}}{(34 + n)\times1.67\times10^{-27}+36\times9.11\times10^{-31}}</math>
|-
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] and [[Evaluate (Maths)|evaluate]] the equation, then [[Solve (Maths)|solve]].'''
There are 24 [[neutron]]s in this isotope of [[Titanium]].
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] and [[Evaluate (Maths)|evaluate]] the equation and , then [[Solve (Maths)|solve]].''' <math>(34 + n)\times1.67\times10^{-27}+36\times9.11\times10^{-31} = \frac{-2\times1.60\times10^{-19}}{-2.46\times10^{6}}</math> <math>(34 + n)\times1.67\times10^{-27}+3.2796\times10^{-29} = 1.3008\times10^{-25}</math> <math>(34 + n) = \frac{1.3008\times10^{-25}-3.2796\times10^{-29}}{1.67\times10^{-27}}</math> <math>(34 + n) = 77.9</math> <math>n = 43.9</math>The [[Atomic Nucleus|nucleus]] contains 44 [[neutron]]s.
|}
====Calculating Atomic Number====
{| class="wikitable"
| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[proton]]s in a [[Atomic Nucleus|atomic nucleus]] of an [[isotope]] with a an [[Relative Atomic Mass|atomic mass]] of ..... 231[[Unified Atomic Mass Units|u]] and a [[Specific Charge|specific charge]] of 3......82x10<sup>7</sup>Ckg<sup>-1</sup>.| style="height:20px; width:300px; text-align:center;" |Calculate the number of [[proton]]s in a [[Atomic Nucleus|atomic nucleus]] of an [[isotope]] with a 30 [[massneutron]] of ..... s and the a [[Specific Charge|specific charge]] of 4....... for its 5+ [[ion]]35x10<sup>7</sup>Ckg<sup>-1</sup>.
|-
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>S.C. = 3.82\times10^{7}</math>Ckg<sup>-1</sup>
<math>Q = z\times1.60\times10^{-19}</math>C
<math>m = 231\times1.67\times10^{-27}</math>kg
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>S.C. = 4.35\times10^{7}</math>Ckg<sup>-1</sup>
<math>Q = z\times1.60\times10^{-19}</math>C
The [[Relative Atomic Mass|atomic mass]] can be approximated as the number of [[nucleon]]s multiplied by the [[Unified Atomic Mass Units|unified atomic mass unit]].
<math>m = (z+30)\times1.67\times10^{-27}</math>kg
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>S.C. = \frac{Q}{m}</math>
<math>3.82\times10^{7} = \frac{z\times1.60\times10^{-19}}{231\times1.67\times10^{-27}}</math>
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>S.C. = \frac{Q}{m}</math>
<math>4.35\times10^{7} = \frac{z\times1.60\times10^{-19}}{(z+30)\times1.67\times10^{-27}}</math>
|-
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>3.82\times10^{7}\times231\times1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>1.4736414\times10^{-17} = z\times1.60\times10^{-19}</math>
<math>z = \frac{1.4736414\times10^{-17}}{1.60\times10^{-19}}</math>
<math>z = 92.1</math>
The [[element]] is [[Uranium]].
| style="height:20px; width:300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>4.35\times10^{7} = \frac{z\times1.60\times10^{-19}}{(z+30)\times1.67\times10^{-27}}</math>
<math>4.35\times10^{7}\times(z+30)\times1.67\times10^{-27} = z\times1.60\times10^{-19}</math>
<math>(z+30)\times7.2645\times10^{-20} = z\times1.60\times10^{-19}</math>
<math>z\times7.2645\times10^{-20} + 30\times7.2645\times10^{-20}= z\times1.60\times10^{-19}</math>
<math>z\times1.60\times10^{-19} - z\times7.2645\times10^{-20} = 30\times7.2645\times10^{-20}</math>
<math>z(1.60\times10^{-19} - 7.2645\times10^{-20}) = 30\times7.2645\times10^{-20}</math>
<math>z = \frac{30\times7.2645\times10^{-20}}{1.60\times10^{-19} - 7.2645\times10^{-20}}</math>
<math>z = 24.9</math>
There are 25 [[proton]]s so the [[element]] is [[Manganese]].
|}