Difference between revisions of "Specific Heat Capacity"
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: The [[SI Unit]]s of '''specific heat capacity''' are J/kg°C. | : The [[SI Unit]]s of '''specific heat capacity''' are J/kg°C. | ||
: '''Specific heat capacity''' describes how easily the [[temperature]] of a [[material]] can be changed. | : '''Specific heat capacity''' describes how easily the [[temperature]] of a [[material]] can be changed. | ||
| + | : Different [[material]]s have a different '''specific heat capacity'''. | ||
: [[Material]]s with a low '''specific heat capacity''' are generally good [[Thermal Conductor|thermal conductors]] and [[material]]s with a high '''specific heat capacity''' are generally good [[Thermal Insulator|thermal insulators]]. | : [[Material]]s with a low '''specific heat capacity''' are generally good [[Thermal Conductor|thermal conductors]] and [[material]]s with a high '''specific heat capacity''' are generally good [[Thermal Insulator|thermal insulators]]. | ||
Revision as of 11:33, 6 March 2019
Contents
Key Stage 4
Meaning
Specific heat capacity is the energy required to increase the temperature of 1kg of a material by 1°C.
About Specific Heat Capacity
- The SI Units of specific heat capacity are J/kg°C.
- Specific heat capacity describes how easily the temperature of a material can be changed.
- Different materials have a different specific heat capacity.
- Materials with a low specific heat capacity are generally good thermal conductors and materials with a high specific heat capacity are generally good thermal insulators.
Equation
NB: You do not need to remember the equation for specific heat capacity.
Specific Heat Capacity = (Energy Transferred)/[(Mass) x (Temperature Change)]
\(c = \frac{E}{m \Delta \theta}\)
Where\[c\] = The Specific Heat Capacity of the material.
\(E\) = The Energy transferred to the object, by heating.
\(m\) = The mass of the object.
\(\Delta \theta\) = The Temperature change of the object.
Example Calculations
| 8.0kg of water is heated with an energy of 1510kJ from a temperature of 11°C to a temperature of 56°C. Calculate the specific heat capacity of the water correct to two significant figures. | A 989g block of metal is heated using an immersion heater from 24°C to 39°C. A Joulemeter connected to the immersion heater reads 13,000J. Calculate the specific heat capacity of the metal correct to two significant figures. |
| 1. State the known quantities in SI Units
E = 1510kJ = 1510x103J m = 8.0kg Δθ = 56-11 = 45°C |
1. State the known quantities in SI Units
E = 13,000J m = 989g = 0.989kg Δθ = 39-24 = 15°C |
| 2. Substitute the numbers into the equation and solve.
\(c = \frac{E}{m \Delta \theta}\) \(c = \frac{1510 \times 10^3}{8.0 \times 45}\) \(c = 4194.4J/kg ^\circ C\) \(c \approx 4200J/kg ^\circ C\) |
2. Substitute the numbers into the equation and solve.
\(c = \frac{E}{m \Delta \theta}\) \(c = \frac{13000}{0.989 \times 15}\) \(c = 876.306033J/kg ^\circ C\) \(c \approx 880J/kg ^\circ C\) |