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Specific Heat Capacity

1,327 bytes added, 10:49, 6 March 2019
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<math>\Delta \theta</math> = The [[Temperature]] change of the [[object]].
 
===Example Calculations===
{| class="wikitable"
| style="height:20px; width:300px; text-align:center;" |8.0kg of [[water]] is [[heat]]ed with an [[energy]] of 1510kJ from a [[temperature]] of 11°C to a [[temperature]] of 56°C. Calculate the '''specific heat capacity of the [[water]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:300px; text-align:center;" |A 989g block of [[metal]] is [[heat]]ed using an [[Immersion Heater|immersion heater]] from 24°C to 39°C. A [[Joulemeter]] connected to the [[Immersion Heater|immersion heater]] reads 13,000J. Calculate the '''specific heat capacity''' of the [[metal]] correct to two [[Significant Figures|significant figures]].
|-
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s'''
 
E = 1510kJ = 1510x10<sup>3</sup>J
 
m = 8.0kg
 
Δθ = 56-11 = 45°C
| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s'''
|-
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''
| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''
|}