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→Calculating Specific Charge
====Calculating Specific Charge====
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| style="height:20px; width:200px300px; text-align:center;" |Find the '''specific charge of a [[proton]].| style="height:20px; width:200px300px; text-align:center;" |Find the '''specific charge''' of a [[Magnesium|Magnesium-24]] 2+ [[ion]].
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| style="height:20px; width:200px300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.''' <math>Q_{proton} = 1\times1.60\times10^{-19}Coulombs</math> <math>Mass_{proton} = 1\times1.67\times10^{-27}kilograms</math> | style="height:20px; width:200px300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.''' The [[Electrical Charge|charge]] on an [[Magnesium|Mg]] 2+ [[ion]] is 2 x [[Elementary Charge|elementary charge]]. <math>Q_{Mg+2} = 2\times1.60\times10^{-19}Coulombs</math> The [[mass]] of [[Magnesium|Magnesium-24]] 2+ [[ion]] is the mass of 24 [[nucleon]]s + 10 [[electron]]s. <math>Mass_{Mg-24} = 24\times1.67\times10^{-27}kilograms + 10\times9.11\times10^{-31}</math>
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| style="height:20px; width:200px300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].''' <math>S.C. = \frac{Q}{m}</math> <math>S.C. = \frac{1\times1.60\times10^{-19}}{1\times1.67\times10^{-27}}</math> | style="height:20px; width:200px300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].''' <math>S.C. = \frac{Q}{m}</math> <math>S.C. = \frac{2\times1.60\times10^{-19}}{24\times1.67\times10^{-27}kilograms + 10\times9.11\times10^{-31}}</math>
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| style="height:20px; width:200px300px; text-align:left;" |'''3. [[Rearrange Solve (Maths)|Rearrangesolve]] the equation and [[Solve (Maths)|solve]].''' <math>S.C. = \frac{Q}{m}</math> <math>S.C. = \frac{1.60\times10^{-19}}{1.67\times10^{-27}}</math> <math>S.C. = 9.58\times10^{7}Ckg^{-1}</math> | style="height:20px; width:200px300px; text-align:left;" |'''3. [[Rearrange Solve (Maths)|Rearrangesolve]] the equation and [[Solve (Maths)|solve]].''' <math>S.C. = \frac{Q}{m}</math> <math>S.C. = \frac{3.20\times10^{-19}}{4.01\times10^{-26}}</math> <math>S.C. = 7.98\times10^{6}Ckg^{-1}</math>
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