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Created page with "==Key Stage 4== ===Meaning=== A limiting reactant is a reactant that is not supplied in a large enough quantity for a complete Chemical Reaction|re..."
==Key Stage 4==
===Meaning===
A [[Limiting Reactant|limiting reactant]] is a [[reactant]] that is not supplied in a large enough quantity for a complete [[Chemical Reaction|reaction]] with the other [[reactant]]s.
===About Limiting Reactants===
: A '''limiting reactant''' prevents a complete [[Chemical Reaction|reaction]].
===Examples===
2H<sub>2</sub>(g) + O<sub>2</sub>(g) → 2H<sub>2</sub>O(l)
: If there is 4g of [[Hydrogen]] then 32g of [[Oxygen]] is needed for a complete [[Chemical Reaction|reaction]] to occur.
: If there is 4g of [[Hydrogen]] but only 31g of [[Oxygen]] then the [[Oxygen]] is a [[Limiting Reactant|limiting reactant]].
: If there is 3g of [[Hydrogen]] but only 32g of [[Oxygen]] then the [[Hydrogen]] is a [[Limiting Reactant|limiting reactant]].
===Finding a Limiting Reactant===
{| class="wikitable"
|-
| style="height:20px; width:250px; text-align:center;" |If there are are 6g of [[Carbon]] and 15g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
C + O<sub>2</sub> → CO<sub>2</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
| style="height:20px; width:250px; text-align:center;" |If there are are 27g of [[Aluminium]] and 32g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
4Al + 3O<sub>2</sub> → 2Al<sub>2</sub>O<sub>3</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
| style="height:20px; width:250px; text-align:center;" |If there are are 180g of [[Glucose]] and 200g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> + 6O<sub>2</sub> → 6H<sub>2</sub>O + 6CO<sub>2</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
|-
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of C = 12g
M<sub>r</sub> of O<sub>2</sub> = 32g
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of NaOH = 40g
M<sub>r</sub> of HCl = 36.5g
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of NaOH = 40g
M<sub>r</sub> of HCl = 36.5g
|-
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
1 [[mole]]s of C is needed for every 1 [[mole]] of O<sub>2</sub>
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
4 [[mole]]s of Al are needed for every 3 [[mole]]s of O<sub>2</sub>
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
1 [[mole]] of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> is needed for every 6 [[mole]]s of O<sub>2</sub>
|-
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of C = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of C = <math>\frac{6}{12}</math>
No. [[Mole]]s = 0.5 mol
Therefore 0.5 [[mole]]s of O<sub>2</sub> is needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{15}{32}</math>
No. [[Mole]]s = 0.46 mol
[[Oxygen]] is the [[Limiting Reactant|limiting reactant]].
1 [[mole]] of O<sub>2</sub> = 32g
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of Al = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of Al = <math>\frac{27}{27}</math>
No. [[Mole]]s = 1 mol
Therefore 0.75 [[mole]]s of O<sub>2</sub> are needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{32}{32}</math>
No. [[Mole]]s = 1 mol
[[Oxygen]] is the [[Limiting Reactant|limiting reactant]].
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> = <math>\frac{180}{180}</math>
No. [[Mole]]s = 1 mol
Therefore 6 [[mole]]s of O<sub>2</sub> are needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{200}{32}</math>
No. [[Mole]]s = 6.25 mol
[[Glucose]] is the [[Limiting Reactant|limiting reactant]].
|}
===Meaning===
A [[Limiting Reactant|limiting reactant]] is a [[reactant]] that is not supplied in a large enough quantity for a complete [[Chemical Reaction|reaction]] with the other [[reactant]]s.
===About Limiting Reactants===
: A '''limiting reactant''' prevents a complete [[Chemical Reaction|reaction]].
===Examples===
2H<sub>2</sub>(g) + O<sub>2</sub>(g) → 2H<sub>2</sub>O(l)
: If there is 4g of [[Hydrogen]] then 32g of [[Oxygen]] is needed for a complete [[Chemical Reaction|reaction]] to occur.
: If there is 4g of [[Hydrogen]] but only 31g of [[Oxygen]] then the [[Oxygen]] is a [[Limiting Reactant|limiting reactant]].
: If there is 3g of [[Hydrogen]] but only 32g of [[Oxygen]] then the [[Hydrogen]] is a [[Limiting Reactant|limiting reactant]].
===Finding a Limiting Reactant===
{| class="wikitable"
|-
| style="height:20px; width:250px; text-align:center;" |If there are are 6g of [[Carbon]] and 15g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
C + O<sub>2</sub> → CO<sub>2</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
| style="height:20px; width:250px; text-align:center;" |If there are are 27g of [[Aluminium]] and 32g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
4Al + 3O<sub>2</sub> → 2Al<sub>2</sub>O<sub>3</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
| style="height:20px; width:250px; text-align:center;" |If there are are 180g of [[Glucose]] and 200g of [[Oxygen]] in the following [[Chemical Reaction|reaction]]:
C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> + 6O<sub>2</sub> → 6H<sub>2</sub>O + 6CO<sub>2</sub>
Which is the [[Limiting Reactant|limiting reactant]] in this [[Chemical Reaction|reaction]]?
|-
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of C = 12g
M<sub>r</sub> of O<sub>2</sub> = 32g
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of NaOH = 40g
M<sub>r</sub> of HCl = 36.5g
| style="height:20px; width:250px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of NaOH = 40g
M<sub>r</sub> of HCl = 36.5g
|-
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
1 [[mole]]s of C is needed for every 1 [[mole]] of O<sub>2</sub>
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
4 [[mole]]s of Al are needed for every 3 [[mole]]s of O<sub>2</sub>
| style="height:20px; width:250px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
1 [[mole]] of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> is needed for every 6 [[mole]]s of O<sub>2</sub>
|-
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of C = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of C = <math>\frac{6}{12}</math>
No. [[Mole]]s = 0.5 mol
Therefore 0.5 [[mole]]s of O<sub>2</sub> is needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{15}{32}</math>
No. [[Mole]]s = 0.46 mol
[[Oxygen]] is the [[Limiting Reactant|limiting reactant]].
1 [[mole]] of O<sub>2</sub> = 32g
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of Al = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of Al = <math>\frac{27}{27}</math>
No. [[Mole]]s = 1 mol
Therefore 0.75 [[mole]]s of O<sub>2</sub> are needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{32}{32}</math>
No. [[Mole]]s = 1 mol
[[Oxygen]] is the [[Limiting Reactant|limiting reactant]].
| style="height:20px; width:250px; text-align:center;" |
Find the number of [[mole]]s supplied of each [[chemical]].
No. [[Mole]]s of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> = <math>\frac{180}{180}</math>
No. [[Mole]]s = 1 mol
Therefore 6 [[mole]]s of O<sub>2</sub> are needed.
No. [[Mole]]s of O = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s of O = <math>\frac{200}{32}</math>
No. [[Mole]]s = 6.25 mol
[[Glucose]] is the [[Limiting Reactant|limiting reactant]].
|}