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|[[File:FlemingsLeftHandRule.png|center|300px]]
|[[File:MotorEffect.png|center|300px]]
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<math>\overrightarrow{F}</math>: The [[force]].
| style="height:20px; width:200px; text-align:left;" |The direction on the [[force]] on this [[wire]] can be found using [[Fleming's Left Hand Rule]].
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===Example Calculations===
{| class="wikitable"
| style="height:20px; width:200px; text-align:center;" |A [[wire]] carrying a [[Electrical Current|current]] of 2.3A is inside a 55mT [[Magnetic Field|magnetic field]] that extends along the [[wire]] by a [[length]] of 6.1cm. Calculate the [[force]] on the [[wire]] correct to two [[Significant Figures|significant figures]].
| style="height:20px; width:200px; text-align:center;" |23cm of [[wire]] carrying 1.2A of [[Electrical Current|current]] is contained in a 37mT [[Magnetic Field|magnetic field]]. Calculate the [[force]] on the [[wire]] correct to two [[Significant Figures|significant figures]].
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| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>B</math> = 55mT = 55x10<sup>-3</sup>T
<math>I</math> = 2.3A
<math>l</math> = 6.1cm = 6.1x10<sup>-2<sup>m
| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s.'''
<math>B</math> = 37mT = 37x10<sup>-3</sup>T
<math>I</math> = 1.2A
<math>l</math> = 23cm = 23x10<sup>-2<sup>m
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| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''
<math>F = BIl</math>
<math>F = 55\times 10^{-3} \times 2.3 \times 6.1 \times 10^{-2}</math>
<math>F = 7.7165 \times 10^{-3}N</math>
<math>F \approx 7.7\times 10^{-3}N</math>
| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''
<math>F = BIl</math>
<math>F = 37\times 10^{-3} \times 1.2 \times 23 \times 10^{-2}</math>
<math>F = 1.0212 \times 10^{-2}N</math>
<math>F \approx 1.0\times 10^{-2}N</math>
|}