Changes

| style="height:20px; width:200px300px; text-align:center;" |5000[[kg]] of [[Iron]] has a [[volume]] of 0.635m³. Calculate the density of [[Iron]] correct to two [[Significant Figures|significant figures]].'''| style="height:20px; width:200px; text-align:center;" |A 50,000cm³ container of [[water]] is full with a 50[[kg]] [[mass]] of [[water]]. Calculate the density of [[water]] correct to two [[Significant Figures|significant figures]].| style="height:20px; width:200px300px; text-align:center;" |A 200,000cm³ [[volume]] of [[air]] has a [[mass]] of 245[[g]]. Calculate the density of [[air]] correct to two [[Significant Figures|significant figures]].

| style="height:20px; width:200px300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' 

| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' [[Mass]] = 245[[g]] = 0.245[[kg]] [[Volume (Space)|Volume]] = 200,000cm³ = 0.2m³| style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' <math>\rho = \frac{m}{V}</math> <math>\rho = \frac{5000}{0.635}</math> <math>\rho = 7874kg/m^3</math> <math>\rho \approx 7900kg/m^3</math>

| style="height:<math>\rho = \frac{5000}{020px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].635}</math>'''

:<math>\rho = 7874kg/\frac{m^3}{V}</math>

:<math>\rho = \approx 7900kg/m^3frac{0.245}{0.2}</math>| style="height:20px; width:200px; text-align:left;" |[[Mass]] = 50[[kg]]

[[Volume (Space)|Volume]] = 50,000cm<sup>3</supmath> \rho = 01.05m<sup>225kg/m^3</supmath>

:<math>\rho = \frac{approx 1.2kg/m}{V}^3</math>|}

====Finding Volume from Mass and Density===={| class="wikitable"| style="height:20px; width: 300px; text-align:center;" |[[Gold]] has a [[density]] of 19320kg/m<mathsup>\rho 3</sup>. 31g of [[Gold]] is used to make a coin. Calculate the [[Volume (Space)|volume]] of this coin correct to two [[Significant Figures|significant figures]].| style= \frac{50}{0"height:20px; width: 300px; text-align:center;" |A 1.05}3ton rock with a [[density]] of 2650kg/m<sup>3</mathsup>is dropped into a swimming pool. Calculate the [[Volume (Space)|volume]] of [[water]] displaced by the rock, correct to two [[Significant Figures|significant figures]].|-| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s'''

ρ = 19320kg/m³ m = 31g = 31x10^-3kg| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' ρ = 2650kg/m³ m = 1.3ton = 1.3x10³kg|-| style="height:20px; width: 300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].''' <math>\rho = 1000kg\frac{m}{V}</math> <math>19320 = \frac{31 \times 10^{-3}}{V}</math>| style="height:20px; width: 300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].''' <math>\rho = \frac{m}{V}</math> <math>2650 = \frac{1.3 \times 10^{3}}{V}</math>|-| style="height:20px; width:200px300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].''' <math>19320V = 31 \times 10^{-3}</math> <math>V = \frac{31 \times 10^{-3}}{19320}</math> <math>V = 1.60455 \times 10^{-6}m^3</math> <math>V \approx 1.6 \times 10^{-6}</math>| style="height:20px; width: 300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].''' <math>2650V = 1.3 \times 10^{3}</math> <math>V = \frac{1.3 \times 10^{3}}{2650}</math> <math>V = 0.490566m^3</math> <math>V \approx 0.49m^3</math>|} ====Finding Massfrom Volume and Density====Petrol mass from volume 719.7 kg/m³chlorine 993 mass in pool {| class="wikitable"| style="height:20px; width: 300px; text-align:center;" |A car is filled with 32 litres of gasoline, which has a [[density]] of 719.7kg/m³. Calculate the [[mass]] of gasoline added to the car, correct to two [[Significant Figures|significant figures]].| style="height:20px; width: 300px; text-align:center;" |A 2,500,000 litre swimming pool is filled with Chlorinated [[water]] which has a density of 993kg/m³. Calculate the [[mass]] of Chlorinated [[water]] in this swimming pool, correct to two [[Significant Figures|significant figures]].|-| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' ρ = 719.7kg/m³ V = 32 litres = 32x10^-3m³| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' ρ = 993kg/m³ V = 2,500,000 litres = 2,500m³|-| style="height:20px; width: 300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]] .''' <math>\rho = \frac{m}{V}</math> <math>719.7 = 245\frac{m}{32\times10^{-3}}</math>| style="height:20px; width: 300px; text-align:left;" |'''2. [[gSubstitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].''' <math>\rho = \frac{m}{V}</math> <math>993 = \frac{m}{2500}</math>|-| style= 0"height:20px; width: 300px; text-align:left;" |'''3.245[[kgRearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].''' <math>m = 719.7 \times 32 \times 10^{-3}</math>

[[Volume (Space)|Volume]] = 200,000cm<sup>3</supmath> m = 023.2m<sup>30304kg</supmath>

:<math>m \rho = \frac{m}{V}approx 23kg</math>| style="height:20px; width: 300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''

:<math>\rho m = 993 \frac{0.245}{0.2}times 2500</math>

:<math>\rho m = 1.225kg/m^32482500kg</math>

:<math>\rho \approx 1.2kg/m^3= 2500000kg</math>