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| style="height:100px; width:200px; text-align:left;"|The two [[force]]s are redrawn in a a [[Scale Diagram]] with scale is 1000N = 1cm placing the start of one [[vector]] [[force]] at the end of the other.
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| style="height:100px; width:400px; text-align:left;" colspan= "3"|This [[Scale Diagram]] shows that the two arrows add to make a length of 9.4cm, which represents 9400N, in a direction of 90° from the [[North]] which is an [[East]]erly Easterly direction.
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The [[force]] from the top tug boat is +1710N to the [[North]] and the force from the bottom tug boat is -1710N to the [[North]] so the total [[force]] [[North]] is zero.
The total [[force]] [[East]] can be calculated by finding the [[base]] of each [[triangle]].
<math>F_x=5000\cos20</math>
<math>F_x=4698N</math>
The [[force]] from the top tug boat is +4698N to the [[East]] and the force from the bottom tug boat is +4698N to the [[East]] so the total [[force]] [[East]] is 9396N.
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