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| style="height:100px; width:200px; text-align:left;"|The two [[force]]s are redrawn in a a [[Scale Diagram]] with scale is 1000N = 1cm placing the start of one [[vector]] [[force]] at the end of the other.
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| style="height:100px; width:400px; text-align:left;" colspan= "3"|This [[Scale Diagram]] shows that the two arrows add to make a length of 9.4cm, which represents 9400N, in a direction of 90° from the [[North]] which is an Easterly direction.
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| style="height:100px; width:200px; text-align:left;"|One of the [[force]]s is redrawn as the hypotenuse of a [[Right Angle Triangle|right angle triangle]] with [[height]] in the [[y-axis]] and [[base]] in the [[x-axis]].
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| style="height:100px; width:400px; text-align:left;" colspan= "3"|The total [[force]] [[North]] can be calculated by finding the [[height]] of each triangle.
<math>F_y=5000\sin20</math>
<math>F_y=1710N</math>
The [[force]] from the top tug boat is +1710N to the [[North]] and the force from the bottom tug boat is -1710N to the [[North]] so the total [[force]] [[North]] is zero.
The total [[force]] East can be calculated by finding the [[base]] of each triangle.