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: 1Al = 1Al
: 2Cl ≠ 3Cl
We need the same number of [[Chlorine]] [[atom]]s on both sides. To do that we can find the [[Lowest Common Multiple]]. In this case it is 6, so we times the left 2 [[Chlorine]]s by 3 and the right 3 [[Chlorine]]s by 2.
: _Al + 3Cl<sub>2</sub> → 2AlCl<sub>3</sub>
: 1Al ≠ 2Al
: 2O ≠ 3O
We need the same number of [[Oxygen]] [[atom]]s on both sides. To do that we can find the [[Lowest Common Multiple]]. In this case it is 6, so we times the left 2 [[Oxygen]]s by 3 and the right 3 [[Oxygen]]s by 2.
: _Al + 3O<sub>2</sub> → 2Al<sub>2</sub>O<sub>3</sub>