V = The total [[Volume (Space)|volume]] taken up by the [[alloy]]
===Examples===
*The ===Example Calculations=======Finding Density from Mass and Volume===={| class="wikitable"|-| style="height:20px; width:300px; text-align:center;" |'''A [[Volume (Space)|volume]] of 6.35x10<sup>-3</sup>m<sup>3</sup> [[Aluminium]] and 4.10x10<sup>-3</sup>m<sup>3</sup> Magnesium are [[alloy]]ed together. Given the densityof [[Aluminium]] is 2700kgm<sup>-3</sup> and the density of [[Magnesium]] is 2700kgm<sup>-3</sup> then calculate the density of the [[alloy]]''' .| style="height:20px; width:300px; text-align:center;" |A 200,000cm<sup>3</sup> [[Volume (Space)|volume]] of [[waterair]] has a [[mass]] is approximately 1000 kgof 245g. Calculate the density of [[air]] correct to two [[Significant Figures|significant figures]].|-| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' [[Aluminium]] [[Volume (Space)|volume]] = 6.35x10<sup>-3</sup>m<sup>3</sup> [[Aluminium]] [[Density]] = 2700kgm<sup>-3</m³sup> [[Magnesium]] [[Volume (Space)|volume]] = 4.10x10<sup>-3</sup>m<sup>3</sup>*The [[Magnesium]] [[Density]] = 1700kgm<sup>-3</sup> | style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s'''density [[Mass]] = 245g = 0.245kg [[Volume (Space)|Volume]] = 200,000cm<sup>3</sup> = 0.2m<sup>3</sup>|-| style="height:20px; width:300px; text-align:left;" |''' of 2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[goldSolve (Maths)|solve]] is much higher than .''' *<math>\rho = \frac{\rho_{Al}V_{Al}+\rho_{Mg}V_{Mg}}{V}</math> *<math>\rho = \frac{2700\times 6.35 \times 10^{-3} + 1700\times 4.10 \times 10^{-3}}{6.35 \times 10^{-3} + 4.10 \times 10^{-3}}</math> *<math>\rho = 2310kgm^{-3}</math> However, this assumes that the total [[Volume (Space)|volume]] of the [[aluminiumobject]], making is simply the [[goldsum]] heavier for of the same two [[Volume (Space)|volumevolumes]] which is not necessarily the case due to the way different sized [[particle]]s form a [[lattice]]. | style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' <math>\rho = \frac{m}{V}</math> <math>\rho = \frac{0.245}{0.2}</math> <math>\rho = 1.225kg/m^3</math> <math>\rho \approx 1.2kg/m^3</math>|}