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Electrical Resistance

1,846 bytes added, 08:23, 26 October 2018
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: V = Potential Difference
: I = Current
 
Calculate the solutions to the worded questions:
a.
b. A bulb has a current of 200mA passing through it and a potential difference of 12V across it. Calculate the resistance of the bulb.
c. State the resistance of a buzzer connected in series to a 6V battery with an ammeter reading of 10mA.
 
 
===Example Calculations===
{| class="wikitable"
|-
| style="height:20px; width:200px; text-align:center;" |'''A student [[measure]]s a [[Potential Difference|potential difference]] of 5[[V]] across a [[component]] and a [[Electrical Current|current]] of 0.1[[A]]. Calculate the resistance.'''
| style="height:20px; width:200px; text-align:center;" |'''A [[Electrical Bulb|bulb]] has a [[Electrical Current|current]] of 200[[mA]] passing through it and a [[Potential Difference|potential difference]] of 12[[V]] across it. Calculate the resistance of the [[Electrical Bulb|bulb]].'''
| style="height:20px; width:200px; text-align:center;" |'''Calculate the resistance of a [[buzzer]] connected in [[Series Circuit|series]] to a 6[[V]] [[battery]] with an [[ammeter]] reading of 10[[mA]].'''
|-
| style="height:20px; width:200px; text-align:left;" |
Force = 40N
 
Distance moved in the direction of the force = 1.2m
 
<math> W = Fd</math>
 
<math> W = 40 \times 1.2</math>
 
<math> W = 48J</math>
| style="height:20px; width:200px; text-align:left;" |
Force = 10,000N
 
Distance moved in the direction of the force = 15m
 
<math> W = Fd</math>
 
<math> W = 10,000 \times 15</math>
 
<math> W = 15,000J</math>
| style="height:20px; width:200px; text-align:left;" |
Force = 40N
 
Distance moved in the direction of the force = 0m
 
<math> W = Fd</math>
 
<math> W = 20 \times 0</math>
 
<math> W = 0J</math>
 
No '''work''' has been done because the movement is not in the direction of the [[force]]. The [[weight]] acts downwards but the movement was horizontal.
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