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→Example Calculations
===Example Calculations===
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Calculate the '''atom economy''' for [[product|producing]] [[Ammonia]] in the following [[Chemical Reaction|reaction]]:
N<sub>2</sub>(g) + 3H<sub>2</sub>(g) ⇌ 2NH<sub>3</sub>(g)
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Calculate the '''atom economy''' for [[product|producing]] [[Calcium Oxide]] in the following [[Chemical Reaction|reaction]]:
CaCO<sub>3</sub>(s) → CaO(s) + CO<sub>2</sub>(g)
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Calculate the '''atom economy''' for [[product|producing]] [[Sodium Chloride]] in the following [[Chemical Reaction|reaction]]:
HCl(aq) + NaOH(aq) → NaCl(aq) + H<sub>2</sub>O(l)
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'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
M<sub>r</sub> of N<sub>2</sub> = 28g
M<sub>r</sub> of H<sub>2</sub> = 2g
M<sub>r</sub> of NH<sub>3</sub> = 17g
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'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
M<sub>r</sub> of CaCO<sub>3</sub> = 100g
M<sub>r</sub> of CaO = 56g
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'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
M<sub>r</sub> of HCl = 36.5g
M<sub>r</sub> of NaOH = 40g
M<sub>r</sub> of NaCl = 58.5g
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'''Find the total [[mass]] of [[reactant]]s needed and the total [[mass]] of the desired [[product]].'''
Mass of Reactants = 28 + 3 x 2
Mass of Reactants = 34g
Mass of desired Product = 2 x 17
Mass of desired Product = 34g
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'''Find the total [[mass]] of [[reactant]]s needed and the total [[mass]] of the desired [[product]].'''
Mass of Reactants = 100g
Mass of desired Product = 56g
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'''Find the total [[mass]] of [[reactant]]s needed and the total [[mass]] of the desired [[product]].'''
Mass of Reactants = 36.5 + 40
Mass of Reactants = 76.5g
Mass of desired Product = 58.5g
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'''Find the number of [[mole]]s supplied of the known [[mass]].'''
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s = <math>\frac{48}{24}</math>
No. [[Mole]]s = 2 mol
Therefore 2 [[mole]]s of MgO is produced.
2 [[mole]]s of MgO = 40x2
'''Yield''' = 80g
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'''Find the number of [[mole]]s supplied of the known [[mass]].'''
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s = <math>\frac{320}{16}</math>
No. [[Mole]]s = 20 mol
Therefore 40 [[mole]]s of H<sub>2</sub>O are produced.
40 [[mole]]s of CO<sub>2</sub> = 18x40
'''Yield''' = 720g
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'''Find the number of [[mole]]s supplied of the known [[mass]].'''
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
No. [[Mole]]s = <math>\frac{7.3}{36.5}</math>
No. [[Mole]]s = 0.2 mol
Therefore 0.2 [[mole]] of [[Sodium Chloride]] is produced.
0.2 [[mole]] of NaCl = 11.7g
'''Yield''' = 11.7g
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