Changes

| style="height:20px; width:200px; text-align:center;" |TextThe [[diagram]] gives the [[magnitude]] of the [[tension]] as 10N and the [[angle]] from the [[horizontal]] as 37°.| style="height:20px; width:200px; text-align:center;" |TextUsing the [[horizontal]] as the [[x-axis]] a [[Right Angle Triangle|right angle triangle]] is drawn with the [[tension]] as the [[hypotenuse]] to show the two [[perpendicular]] components.|-| style="height:20px; width:600px; text-align:center;"; colspan = "2" |The component needed is the [[Adjacent (Trigonometry)|adjacent]] to the [[angle]] in the [[Right Angle Triangle|right angle triangle]] so [[cosine]] should be used. <math>F_x = 10\cos37</math> <math>F_x = 7.9863551N</math> <math>F_x \approx 8.0N</math>

|+ Calculate the component of the [[tensionweight]] acting against [[friction]]down the slope.

| style="height:20px; width:200px; text-align:center;" |TextThe [[diagram]] gives the [[magnitude]] of the [[weight]] as 39N and the [[angle]] of the slope as 22.6°.| style="height:20px; width:200px; text-align:center;" |TextUsing the slope as the [[x-axis]] a [[Right Angle Triangle|right angle triangle]] is drawn with the [[weight]] as the [[hypotenuse]] to show the two [[perpendicular]] components. The [[angle]] at the bottom of this [[triangle]] is the same as the [[angle]] of the slope.|-| style="height:20px; width:600px; text-align:center;"; colspan = "2" |The component needed is the [[Opposite (Trigonometry)|opposite]] to the [[angle]] in the [[Right Angle Triangle|right angle triangle]] so [[sine]] should be used. <math>F_x = 39\sin22.6</math> <math>F_x = 14.98751758N</math> <math>F_x \approx 15N</math>