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→Finding Energy Transferred from Charge and Potential Difference
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| style="height:20px; width: 300px; text-align:left;" |'''1. State the known quantities in correct [[unit]]s.'''
V = 31,000kV = 3.1x10<sup>7<sup>V
Q = 15C
| style="height:20px; width: 300px; text-align:left;" |'''1. State the known quantities in correct [[unit]]s.'''
V = 9V
Q = 4.3kC = 4.3x10<sup>3</sup>
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| style="height:20px; width: 300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>Q=\frac{E}{V}</math>
<math>15=\frac{E}{3.1 \times 10^7}</math>
| style="height:20px; width: 300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers and [[Evaluate (Maths)|evaluate]].'''
<math>Q=\frac{E}{V}</math>
<math>4.3 \times 10^3 =\frac{E}{9}</math>
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| style="height:20px; width: 300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>E = 15 \times 3.1 \times 10^7</math>
<math>E = 4.65\times10^8 J</math>
<math>E\approx4.7\times10^8 J</math>
| style="height:20px; width: 300px; text-align:left;" |'''3. [[Rearrange (Maths)|Rearrange]] the equation and [[Solve (Maths)|solve]].'''
<math>E = 4.3 \times 10^3 \times 9</math>
<math>E = 38700J</math>
<math>E \approx 39000 \times 10^4J</math>
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