===About Atom Economy===
: During a [[Chemical Reaction|chemical reaction]] there is often more than one [[product]]. When there is more than one [[product]] often one is desired and one is a [[Waste Product|waste product]] that must be [[disposal|disposed]] of.: To reduce costs and increase the [[efficiency]] of a process [[Chemical Engineer|chemical engineers]] design systems that [[product|produce]] the maximum amount of a desired [[product]] and a minimum amount of [[Waste Products|waste products]].
===Atom Economy Equation===
Percentage Atom Economy = [(Relative Formula Mass of Desired Product)/(Sum of Relative Formula Masses of Reactants)] x 100%
'' '''% Atom Economy ''' '' = <math>\frac{M_desiredproductM_p}{M_allreactantsM_r}\times 100%</math>
Where:
M<sub>desiredproductp</sub> = Relative Formula Mass of Desired Product
M<sub>allreactantsr</sub> = Sum of Relative Formula Masses of Reactants
===Example Calculations===
| style="height:20px; width:300px; text-align:left;" |
'''Find Substitute the number of [[mole]]s supplied of values into the known [[mass]]equation.'''
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{MassM_p}{M_r}\times 100%</math>
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{4834}{2434}\times 100%</math>
No. [[Mole]]s = 2 mol Therefore 2 [[mole]]s of MgO is produced. 2 [[mole]]s of MgO = 40x2 '''Yield''% Atom Economy''''' = 80g100%
| style="height:20px; width:300px; text-align:left;" |
'''Find Substitute the number of [[mole]]s supplied of values into the known [[mass]]equation.'''
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{MassM_p}{M_r}\times 100%</math>
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{32056}{16100}\times 100%</math>
No. [[Mole]]s = 20 mol Therefore 40 [[mole]]s of H<sub>2</sub>O are produced. 40 [[mole]]s of CO<sub>2</sub> = 18x40 '''Yield''% Atom Economy''''' = 720g56%
| style="height:20px; width:300px; text-align:left;" |
'''Find Substitute the number of [[mole]]s supplied of values into the known [[mass]]equation.'''
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{MassM_p}{M_r}\times 100%</math>
No. [[Mole]]s '' '''% Atom Economy''' '' = <math>\frac{758.35}{3676.5}\times 100%</math>
No. [[Mole]]s '' '''% Atom Economy''' '' = 076.2 mol5%Therefore 0.2 [[mole]] of [[Sodium Chloride]] is produced.|}
0===References=======AQA====:[https://www.amazon.co.2 uk/gp/product/1471851346/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1471851346&linkCode=as2&tag=nrjc-21&linkId=3ac654f4b0da781c49c855a1af4c92ea ''Atom economy (atom utilisation), pages 79-80, GCSE Chemistry, Hodder, AQA '']:[https://www.amazon.co.uk/gp/product/1782945571/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945571&linkCode=as2&tag=nrjc-21&linkId=9e29fad914244909903e5e93f8a01d47 ''Atom economy, page 48, GCSE Chemistry; The Revision Guide, CGP, AQA '']:[molehttps://www.amazon.co.uk/gp/product/1782945962/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945962&linkCode=as2&tag=nrjc-21&linkId=476bb5c8d1dfb5c08ac81b6d4d1c98d8 ''Atom economy, pages 138-140, GCSE Chemistry, CGP, AQA '']:[https://www.amazon.co.uk/gp/product/0198359381/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359381&linkCode=as2&tag=nrjc-21&linkId=47c8d1ae58d8b3a5e2094cd447154558 ''Atom economy, pages 70-71, GCSE Chemistry; Third Edition, Oxford University Press, AQA ''] of NaCl :[https://www.amazon.co.uk/gp/product/0008158762/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158762&linkCode=as2&tag=nrjc-21&linkId=a0fffa35b3ea49a63404f6704e0df7cc ''Atom; atom economy (atom utilisation), pages 97, 116-7, 323, 325, GCSE Chemistry; Student Book, Collins, AQA '']====Edexcel==== 11:[https://www.7gamazon.co.uk/gp/product/1782945725/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945725&linkCode=as2&tag=nrjc-21&linkId=694be7494de75af3349537d34e13f7f0 ''Atom economies, page 67, GCSE Chemistry; The Revision Guide, CGP, Edexcel '']:[https://www.amazon.co.uk/gp/product/1782948147/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948147&linkCode=as2&tag=nrjc-21&linkId=f63dcd8345f4e49c717b39a228a36c7c ''Atom economies, pages 192-194, GCSE Chemistry, CGP, Edexcel '']:[https://www.amazon.co.uk/gp/product/1292120215/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120215&linkCode=as2&tag=nrjc-21&linkId=8f96ddb76196848bafdb124354e4cf77 ''Atom economy, pages 110-111, GCSE Chemistry, Pearson, Edexcel '']
====OCR====:[https://www.amazon.co.uk/gp/product/0198359829/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359829&linkCode=as2&tag=nrjc-21&linkId=90e8d7b4f039d53035238fa0320fe00b ''Atom economies, page 161, Gateway GCSE Chemistry, Oxford, OCR '']:[https://www.amazon.co.uk/gp/product/1782945679/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945679&linkCode=as2&tag=nrjc-21&linkId=a2db42f7b4bdf10cafaafa3bb9120940 'Yield'Atom economy, page 67, GCSE Chemistry; The Revision Guide, CGP, OCR Gateway '' = 11.7g|}]