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Difference between revisions of "Atom Economy"

(Atom Economy Equation)
(Example Calculations)
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'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+
'''Substitute the values into the equation.'''
  
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
+
'' '''% Atom Economy''' '' = <math>\frac{M_p}{M_r} \times 100%</math>
  
No. [[Mole]]s = <math>\frac{48}{24}</math>
+
'' '''% Atom Economy''' '' = <math>\frac{34}{34} \times 100%</math>
  
No. [[Mole]]s = 2 mol
+
'' '''% Atom Economy''' '' = 100%
 
 
Therefore 2 [[mole]]s of MgO is produced.
 
 
 
2 [[mole]]s of MgO = 40x2
 
 
 
'''Yield''' = 80g
 
  
 
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| style="height:20px; width:300px; text-align:left;" |
'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+
'''Substitute the values into the equation.'''
  
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
+
'' '''% Atom Economy''' '' = <math>\frac{M_p}{M_r} \times 100%</math>
  
No. [[Mole]]s = <math>\frac{320}{16}</math>
+
'' '''% Atom Economy''' '' = <math>\frac{56}{100} \times 100%</math>
  
No. [[Mole]]s = 20 mol
+
'' '''% Atom Economy''' '' = 56%
 
 
Therefore 40 [[mole]]s of H<sub>2</sub>O are produced.
 
 
 
40 [[mole]]s of CO<sub>2</sub> = 18x40
 
 
 
'''Yield''' = 720g
 
  
 
| style="height:20px; width:300px; text-align:left;" |
 
| style="height:20px; width:300px; text-align:left;" |
'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+
'''Substitute the values into the equation.'''
 
 
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
 
 
 
No. [[Mole]]s = <math>\frac{7.3}{36.5}</math>
 
 
 
No. [[Mole]]s = 0.2 mol
 
  
Therefore 0.2 [[mole]] of [[Sodium Chloride]] is produced.
+
'' '''% Atom Economy''' '' = <math>\frac{M_p}{M_r} \times 100%</math>
  
0.2 [[mole]] of NaCl = 11.7g
+
'' '''% Atom Economy''' '' = <math>\frac{58.5}{76.5} \times 100%</math>
  
'''Yield''' = 11.7g
+
'' '''% Atom Economy''' '' = 76.5%
 
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Revision as of 19:48, 27 January 2019

Key Stage 4

Meaning

Atom Economy is the percentage of atoms in the reactants which ends up in the desired products.

About Atom Economy

During a chemical reaction there is often more than one product. When there is more than one product often one is desired and one is a waste product that must be disposed of.
To reduce costs and increase the efficiency of a process chemical engineers design systems that produce the maximum amount of a desired product and a minimum amount of waste products.

Atom Economy Equation

Percentage Atom Economy = [(Relative Formula Mass of Desired Product)/(Sum of Relative Formula Masses of Reactants)] x 100%

% Atom Economy = \(\frac{M_p}{M_r} \times 100%\)

Where:

Mp = Relative Formula Mass of Desired Product

Mr = Sum of Relative Formula Masses of Reactants

Example Calculations

Calculate the atom economy for producing Ammonia in the following reaction: N2(g) + 3H2(g) ⇌ 2NH3(g)

Calculate the atom economy for producing Calcium Oxide in the following reaction: CaCO3(s) → CaO(s) + CO2(g)

Calculate the atom economy for producing Sodium Chloride in the following reaction: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

Find the Relative Formula Mass of the relevant reactants and product.

Mr of N2 = 28g

Mr of H2 = 2g

Mr of NH3 = 17g

Find the Relative Formula Mass of the relevant reactants and product.

Mr of CaCO3 = 100g

Mr of CaO = 56g

Find the Relative Formula Mass of the relevant reactants and product.

Mr of HCl = 36.5g

Mr of NaOH = 40g

Mr of NaCl = 58.5g

Find the total mass of reactants needed and the total mass of the desired product.

Mass of Reactants = 28 + 3 x 2

Mass of Reactants = 34g

Mass of desired Product = 2 x 17

Mass of desired Product = 34g

Find the total mass of reactants needed and the total mass of the desired product.

Mass of Reactants = 100g

Mass of desired Product = 56g

Find the total mass of reactants needed and the total mass of the desired product.

Mass of Reactants = 36.5 + 40

Mass of Reactants = 76.5g

Mass of desired Product = 58.5g

Substitute the values into the equation.

% Atom Economy = \(\frac{M_p}{M_r} \times 100%\)

% Atom Economy = \(\frac{34}{34} \times 100%\)

% Atom Economy = 100%

Substitute the values into the equation.

% Atom Economy = \(\frac{M_p}{M_r} \times 100%\)

% Atom Economy = \(\frac{56}{100} \times 100%\)

% Atom Economy = 56%

Substitute the values into the equation.

% Atom Economy = \(\frac{M_p}{M_r} \times 100%\)

% Atom Economy = \(\frac{58.5}{76.5} \times 100%\)

% Atom Economy = 76.5%