20g + x = y + z
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Find the [[Relative Formula Mass]] of the [[reactant]]s.
Mg = 24g
O<sub>2</sub> = 16x2
O<sub>2</sub> = 32g
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x = 25g - 11g
x = 14g
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20g = 9g + x
x |-| style= 20g "height:20px; width:200px; text- 9galign:center;" |State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
x = 11g2 [[mole]]s of Magnesium are needed for every one [[mole]] of O<sub>2</sub>
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160g + x | style= 306g"height:20px; width:200px; text-align:center;" ||-| style="height:20px; width:200px; text-align:center;" |Find the number of [[mole]]s supplied of the known [[mass]].
x No. [[Mole]]s = 306g - 160g<math>/frac{Mass}{M_r}</math>
x No. [[Mole]]s = 146g<math>/frac{48}{24}</math> No. [[Mole]]s = 2 Mole Therefore 1 [[mole]] of O<sub>2</sub> needed. 1 [[mole]] of O<sub>2</sub> = 32g | style="height:20px; width:200px; text-align:center;" || style="height:20px; width:200px; text-align:center;" |
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