Open main menu

Changes

Conservation of Mass

1,116 bytes added, 13:35, 3 January 2019
Calculating the Mass Required for a Complete Reaction
Find the [[Relative Formula Mass]] of the [[reactant]]s.
M<sub>r</sub> of Mg = 24g
M<sub>r</sub> of O<sub>2</sub> = 16x2
M<sub>r</sub> of O<sub>2</sub> = 32g
| style="height:20px; width:200px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
 
M<sub>r</sub> of CH<sub>4</sub> = 16g
 
M<sub>r</sub> of O<sub>2</sub> = 16x2
 
M<sub>r</sub> of O<sub>2</sub> = 32g
| style="height:20px; width:200px; text-align:center;" |
Find the [[Relative Formula Mass]] of the [[reactant]]s.
 
M<sub>r</sub> of NaOH = 40g
 
M<sub>r</sub> of HCl = 36.5g
|-
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
2 [[mole]]s of Magnesium Mg are needed for every one 1 [[mole]] of O<sub>2</sub>
| style="height:20px; width:200px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
 
1 [[mole]] of CH<sub>4</sub> is needed for every 2 [[mole]]s of O<sub>2</sub>
 
| style="height:20px; width:200px; text-align:center;" |
State the [[ratio]] of [[mole]]s of each [[chemical]] needed.
 
1 [[mole]] of HCl are needed for every 1 [[mole]] of NaOH
 
|-
 
| style="height:20px; width:200px; text-align:center;" |
Find the number of [[mole]]s supplied of the known [[mass]].
No. [[Mole]]s = 2 Mole
Therefore 1 [[mole]] of O<sub>2</sub> is needed.
1 [[mole]] of O<sub>2</sub> = 32g
| style="height:20px; width:200px; text-align:center;" |
Find the number of [[mole]]s supplied of the known [[mass]].
 
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
 
No. [[Mole]]s = <math>\frac{32}{16}</math>
 
No. [[Mole]]s = 2 Mole
 
Therefore 4 [[mole]]s of O<sub>2</sub> are needed.
 
4 [[mole]]s of O<sub>2</sub> = 128g
 
| style="height:20px; width:200px; text-align:center;" |
Find the number of [[mole]]s supplied of the known [[mass]].
 
No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
 
No. [[Mole]]s = <math>\frac{20}{40}</math>
 
No. [[Mole]]s = 0.5 Mole
 
Therefore 0.5 [[mole]] of HCl is needed.
 
0.5 [[mole]] of HCl = 18.25g
 
|}