Changes

: The [[distance]] travelled can be calculated from a '''velocity-time graph''' by breaking the [[graph]] into simple shapes and finding the [[area]] of those shapes. This may use the equations <math>a area = b base \times hheight</math> for rectangular shapes and <math>a area = \frac{b base \times hheight}{2}</math> for triangular shapes.

| style="height:20px; width:300px200px; text-align:left;" |'''Calculate 1. State the known quantities'''base = 8s height = 30m/s| style="height:20px; width:200px; text-align:left;" |'''1. State the known quantities'''base = 8s height = 40m/s|-| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' <math>area = b \times h</math> <math>area = 8 \times 30</math> <math>area = distance= 250m</math>| style="height:20px; width:200px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] travelled by the numbers into the [[objectequation]] and [[Solve (Maths)|solve]] in this journey.''' <math>area = \frac{b \times h}{2}</math> <math>area = \frac{8 \times 40}{2}</math>

| style<math>area ="height:20px; width:300px; text-align:left;" |'''Calculate the [[distance]] travelled by the [[object]] in this journey.'''\frac{320}{2}</math>