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→Finding the Empirical Formula
| style="height:20px; width:200px; text-align:center;" |416g of [[Sulphur]] is found to [[Chemical Reaction|react]] completely with [[Oxygen]] to produce 832g of [[product]]. Find the '''empirical formula''' for the [[product]].
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| style="height:20px; width:200px; text-align:left;" |State the [[mass]] of all [[reactant]]s.
[[Mass]] of [[Oxygen]] = 64g
[[Mass]] of [[Hydrogen]] = 8g
| style="height:20px; width:200px; text-align:left;" |State the [[mass]] of all [[reactant]]s.
[[Mass]] of [[Carbon]] = 60g
[[Mass]] of [[Oxygen]] = 416g
| style="height:20px; width:200px; text-align:left;" |State the [[mass]] of all [[reactant]]s.
[[Mass]] of [[Sulphur]] = 416g
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| style="height:20px; width:200px; text-align:left;" |Find the number of [[mole]]s of each [[element]].
Number of [[Mole]]s = ([[Mass]]/[[Relative Atomic Mass]])
[[Mole]]s of [[Hydrogen]] = 8 mole
| style="height:20px; width:200px; text-align:left;" |Find the number of [[mole]]s of each [[element]].
Number of [[Mole]]s = ([[Mass]]/[[Relative Atomic Mass]])
[[Mole]]s of [[Oxygen]] = 10 mole
| style="height:20px; width:200px; text-align:left;" |Find the number of [[mole]]s of each [[element]].
Number of [[Mole]]s = ([[Mass]]/[[Relative Atomic Mass]])
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| style="height:20px; width:200px; text-align:left;" |Find the [[Ratio]]:
[[Hydrogen]]:[[Oxygen]]
2:1
| style="height:20px; width:200px; text-align:left;" |Find the [[Ratio]]:
[[Carbon]]:[[Oxygen]]
1:2
| style="height:20px; width:200px; text-align:left;" |Find the [[Ratio]]:
[[Sulphur]]:[[Oxygen]]