Changes

====Density of a single material===='''Density''' of a [[material]] is given by the formula:

===Examples=Density of a composite or alloy material====

*<math>\rho = \frac{\rho_1V_1+\rho_2V_2}{V}</math> *<math>\rho = \frac{\rho_1V_1}{V}+\frac{\rho_2V_2}{V}</math> *<math>\rho = \frac{\rho_1V_1+\rho_2V_2}{V_1+V_2}</math> ρ = The [[density]] of the [[alloy]] ρ₁ = The [[density]] of one of the [[alloy]] composites ρ₂ = The [[density]] of the other [[alloy]] composite V₁ = The [[Volume (Space)|volume]] of one of the [[alloy]] composites V₂ = The [[Volume (Space)|volume]] of the other [[alloy]] composite V = The total [[Volume (Space)|volume]] taken up by the [[alloy]] ===Example Calculations=======Finding Density of an Alloy given the density and volume of its composites===={| class="wikitable"|-| style="height:20px; width:300px; text-align:center;" |'''A [[Volume (Space)|volume]] of 6.35x10^-3m³ [[Aluminium]] and 4.10x10^-3m³ [[Magnesium]] are [[alloy]]ed together. Given the density of [[Aluminium]] is 2700kgm^-3 and the density of [[Magnesium]] is 1700kgm^-3 then calculate the densityof the [[alloy]]'''. | style="height:20px; width:300px; text-align:center;" |''' A [[Volume (Space)|volume]] of 4.9x10^-3m³ [[Copper]] and 1.1x10^-3m³ [[Zinc]] are [[alloy]]ed together. Given the density of [[Copper]] is 8900kgm^-3 and the density of [[waterZinc]] is approximately 1000 kg7100kgm<sup>-3</m³sup> then calculate the density of the [[alloy]]'''.*The |-| style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' [[Aluminium]] [[Volume (Space)|volume]] = 6.35x10^-3m³ [[Aluminium]] [[Density]] = 2700kgm^-3 [[Magnesium]] [[Volume (Space)|volume]] = 4.10x10^-3m³ [[Magnesium]] [[Density]] = 1700kgm^-3 | style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities in [[SI Unit]]s''' [[Copper]] [[Volume (Space)|volume]] = 4.9x10^-3m³ [[Copper]] [[Density]] = 8900kgm^-3 [[Zinc]] [[Volume (Space)|volume]] = 1.1x10^-3m³ [[Zinc]] [[Density]] = 7100kgm^-3 |-| style="height:20px; width:300px; text-align:left;" |'''density2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].'''  *<math>\rho = \frac{\rho_{Al}V_{Al}+\rho_{Mg}V_{Mg}}{V_{Al}+V_{Mg}}</math> *<math>\rho = \frac{2700\times 6.35 \times 10^{-3} + 1700\times 4.10 \times 10^{-3}}{6.35 \times 10^{-3} + 4.10 \times 10^{-3}}</math> *<math>\rho = 2310kgm^{-3}</math> However, this assumes that the total [[Volume (Space)|volume]] of the [[goldobject]] is much higher than simply the [[sum]] of the two [[Volume (Space)|volumes]] which is not necessarily the case due to the way different sized [[particle]]s form a [[lattice]].  | style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' *<math>\rho = \frac{\rho_{Cu}V_{Cu}+\rho_{Zn}V_{Zn}}{V_{Cu}+V_{Zn}}</math> *<math>\rho = \frac{8900\times 4.9 \times 10^{-3} + 7100\times 1.1 \times 10^{-3}}{4.9 \times 10^{-3} + 1.1 \times 10^{-3}}</math> *<math>\rho = 8600kgm^{-3}</math> However, this assumes that the total [[Volume (Space)|volume]] of the [[aluminiumobject]], making is simply the [[goldsum]] heavier for of the same two [[Volume (Space)|volumevolumes]] which is not necessarily the case due to the way different sized [[particle]]s form a [[lattice]].|}