Difference between revisions of "Yield (Chemistry)"

Latest revision as of 12:15, 25 December 2019

Key Stage 4

Meaning

Yield is the mass of product in a chemical reaction.

About Yield

The theoretical yield of product from a chemical reaction can be calculated using the balanced symbol equation and the relative formula masses of all the molecules involved.

The experimental yield from a chemical reaction is often not as large as the theoretical yield because not all of the reactants will react. This experimental yield is often expressed as a percentage of the theoretical yield and is known as the Percentage Yield.

Examples

Calculate the yield of Magnesium Oxide given 48g of Magnesium and excess Oxygen.	Find the yield of Water when 320g of Methane reacts with excess Oxygen.	Find the yield of Sodium Chloride when 7.3 of Hydrochloric Acid reacts with excess Sodium Hydroxide.
Write the Balanced Symbol Equation 2Mg + O₂ → 2MgO	Write the Balanced Symbol Equation CH₄ + 2O₂ → 2H₂O + CO₂	Write the Balanced Symbol Equation NaOH + HCl → NaCl + H₂O
Find the Relative Formula Mass of the relevant reactants and product. M_r of Mg = 24g M_r of MgO = 40g	Find the Relative Formula Mass of the relevant reactants and product. M_r of CH₄ = 16g M_r of H₂O = 18g	Find the Relative Formula Mass of the relevant reactants and product. M_r of NaOH = 40g M_r of HCl = 36.5g M_r of NaCl = 58.5g
State the ratio of moles of each chemical needed. 2 moles of Mg are needed for every 2 moles of MgO	State the ratio of moles of each chemical needed. 1 mole of CH₄ is needed for every 2 moles H₂O	State the ratio of moles of each chemical needed. 1 mole of HCl and NaOH are needed for every 1 mole of NaCl
Find the number of moles supplied of the known mass. No. Moles = \(\frac{Mass}{M_r}\) No. Moles = \(\frac{48}{24}\) No. Moles = 2 mol Therefore 2 moles of MgO is produced. 2 moles of MgO = 40x2 Yield = 80g	Find the number of moles supplied of the known mass. No. Moles = \(\frac{Mass}{M_r}\) No. Moles = \(\frac{320}{16}\) No. Moles = 20 mol Therefore 40 moles of H₂O are produced. 40 moles of CO₂ = 18x40 Yield = 720g	Find the number of moles supplied of the known mass. No. Moles = \(\frac{Mass}{M_r}\) No. Moles = \(\frac{7.3}{36.5}\) No. Moles = 0.2 mol Therefore 0.2 mole of Sodium Chloride is produced. 0.2 mole of NaCl = 11.7g Yield = 11.7g

References

@@ Line 1: / Line 1: @@
 ==Key Stage 4==
 ===Meaning===
-[[Yield]] is the [[mass]] of [[product]] in a [[Chemical Reaction|chemical reaction]].
+'''Yield''' is the [[mass]] of [[product]] in a [[Chemical Reaction|chemical reaction]].
 ===About Yield===
+: The theoretical '''yield''' of [[product]] from a [[Chemical Reaction|chemical reaction]] can be calculated using the [[Balanced Symbol Equation|balanced symbol equation]] and the [[Relative Formula Mass|relative formula masses]] of all the [[molecule]]s involved.
+: The experimental '''yield''' from a [[Chemical Reaction|chemical reaction]] is often not as large as the theoretical '''yield''' because not all of the [[reactant]]s will [[Chemical Reaction|react]]. This experimental '''yield''' is often expressed as a [[percentage]] of the theoretical '''yield''' and is known as the [[Percentage Yield]].
+===Examples===
+{| class="wikitable"
+| style="height:20px; width:300px; text-align:center;" |
+Calculate the '''yield''' of [[Magnesium Oxide]] given 48g of [[Magnesium]] and excess [[Oxygen]].
+| style="height:20px; width:300px; text-align:center;" |
+Find the '''yield''' of [[Water]] when 320g of [[Methane]] [[Chemical reaction|reacts]] with excess [[Oxygen]].
+| style="height:20px; width:300px; text-align:center;" |
+Find the '''yield''' of [[Sodium Chloride]] when 7.3 of [[Hydrochloric Acid]] [[Chemical Reaction|reacts]] with excess [[Sodium Hydroxide]].
+|-
+| style="height:20px; width:300px; text-align:center;" |
+'''Write the Balanced Symbol Equation'''
+Mg + O<sub>2</sub> → 2MgO
+| style="height:20px; width:300px; text-align:center;" |
+'''Write the Balanced Symbol Equation'''
+CH<sub>4</sub> + 2O<sub>2</sub> → 2H<sub>2</sub>O + CO<sub>2</sub>
+| style="height:20px; width:300px; text-align:center;" |
+'''Write the Balanced Symbol Equation'''
+NaOH + HCl → NaCl + H<sub>2</sub>O
+|-
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
+M<sub>r</sub> of Mg = 24g
+M<sub>r</sub> of MgO = 40g
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
+M<sub>r</sub> of CH<sub>4</sub> = 16g
+M<sub>r</sub> of H<sub>2</sub>O = 18g
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the [[Relative Formula Mass]] of the relevant [[reactant]]s and [[product]].'''
+M<sub>r</sub> of NaOH = 40g
+M<sub>r</sub> of HCl = 36.5g
+M<sub>r</sub> of NaCl = 58.5g
+|-
+| style="height:20px; width:300px; text-align:left;" |
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
+[[mole]]s of Mg are needed for every 2 [[mole]]s of MgO
+| style="height:20px; width:300px; text-align:left;" |
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
+[[mole]] of CH<sub>4</sub> is needed for every 2 [[mole]]s H<sub>2</sub>O
+| style="height:20px; width:300px; text-align:left;" |
+'''State the [[ratio]] of [[mole]]s of each [[chemical]] needed.'''
+[[mole]] of HCl and NaOH are needed for every 1 [[mole]] of NaCl
+|-
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
+No. [[Mole]]s = <math>\frac{48}{24}</math>
+No. [[Mole]]s = 2 mol
+Therefore 2 [[mole]]s of MgO is produced.
+[[mole]]s of MgO = 40x2
+'''Yield''' = 80g
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
+No. [[Mole]]s = <math>\frac{320}{16}</math>
+No. [[Mole]]s = 20 mol
+Therefore 40 [[mole]]s of H<sub>2</sub>O are produced.
+[[mole]]s of CO<sub>2</sub> = 18x40
+'''Yield''' = 720g
+| style="height:20px; width:300px; text-align:left;" |
+'''Find the number of [[mole]]s supplied of the known [[mass]].'''
+No. [[Mole]]s = <math>\frac{Mass}{M_r}</math>
+No. [[Mole]]s = <math>\frac{7.3}{36.5}</math>
+No. [[Mole]]s = 0.2 mol
+Therefore 0.2 [[mole]] of [[Sodium Chloride]] is produced.
+.2 [[mole]] of NaCl = 11.7g
+'''Yield''' = 11.7g
+|}
+===References===
+====AQA====
+:[https://www.amazon.co.uk/gp/product/0008158754/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158754&linkCode=as2&tag=nrjc-21&linkId=27ad53b0283feeff7fc5ae04a9e205f621 ''Yield, page 66-7, GCSE Biology; Student Book, Collins, AQA '']
+:[https://www.amazon.co.uk/gp/product/1471851346/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1471851346&linkCode=as2&tag=nrjc-21&linkId=3ac654f4b0da781c49c855a1af4c92ea ''Yield, page 78, GCSE Chemistry, Hodder, AQA '']
+:[https://www.amazon.co.uk/gp/product/178294639X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=178294639X&linkCode=as2&tag=nrjc-21&linkId=51599bb45a2bfaf7c1b6a978b2ca2616 ''Yield, pages 184-186, GCSE Combined Science Trilogy; Chemistry, CGP, AQA '']
+:[https://www.amazon.co.uk/gp/product/0198359381/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359381&linkCode=as2&tag=nrjc-21&linkId=47c8d1ae58d8b3a5e2094cd447154558 ''Yield, pages 68-71, GCSE Chemistry; Third Edition, Oxford University Press, AQA '']
+:[https://www.amazon.co.uk/gp/product/0008158762/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158762&linkCode=as2&tag=nrjc-21&linkId=a0fffa35b3ea49a63404f6704e0df7cc ''Yield, pages 97, 216-219, 317, 323, GCSE Chemistry; Student Book, Collins, AQA '']
+:[https://www.amazon.co.uk/gp/product/1782945962/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945962&linkCode=as2&tag=nrjc-21&linkId=476bb5c8d1dfb5c08ac81b6d4d1c98d8 ''Yields, pages 141, 144, 216-218, GCSE Chemistry, CGP, AQA '']
+:[https://www.amazon.co.uk/gp/product/1782945571/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945571&linkCode=as2&tag=nrjc-21&linkId=9e29fad914244909903e5e93f8a01d272 ''Yields, pages 45, 49, GCSE Chemistry; The Revision Guide, CGP, AQA '']
+====Edexcel====
+:[https://www.amazon.co.uk/gp/product/1782948147/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782948147&linkCode=as2&tag=nrjc-21&linkId=f63dcd8345f4e49c717b39a228a36c7c ''Yields, pages 172-174, 189-191, 201-203, GCSE Chemistry, CGP, Edexcel '']
+:[https://www.amazon.co.uk/gp/product/1782945725/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945725&linkCode=as2&tag=nrjc-21&linkId=694be7494de75af3349537d34e13f7f0 ''Yields, pages 66, 68, GCSE Chemistry; The Revision Guide, CGP, Edexcel '']
+====OCR====
+:[https://www.amazon.co.uk/gp/product/0198359829/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0198359829&linkCode=as2&tag=nrjc-21&linkId=90e8d7b4f039d53035238fa0320fe00b ''Yield, pages 158-161, 190, 200-203, 205, Gateway GCSE Chemistry, Oxford, OCR '']
+:[https://www.amazon.co.uk/gp/product/1782945679/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945679&linkCode=as2&tag=nrjc-21&linkId=a2db42f7b4bdf10cafaafa3bb9120940 ''Yield, pages 66, 74, 80, 82, Gateway GCSE Chemistry; The Revision Guide, CGP, OCR '']
+:[https://www.amazon.co.uk/gp/product/1782945660/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945660&linkCode=as2&tag=nrjc-21&linkId=83aa4500ad7759e7f401a1c5ba5df758 ''Yields (in agriculture), pages 86, 87, Gateway GCSE Biology; The Revision Guide, CGP, OCR '']