Difference between revisions of "Mole"
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==Key Stage 4== | ==Key Stage 4== | ||
===Meaning=== | ===Meaning=== | ||
− | A [[mole]] is an [[SI Unit]] used to show [[ | + | A [[mole]] is an [[SI Unit]] used to show [[Avogadro Constant|6.02x10<sup>23</sup>]] [[particle]]s of a [[chemical]]. |
===About Moles=== | ===About Moles=== | ||
: [[Mole]]s are based on the number of [[Carbon]] [[atom]]s in exactly 0.012kg (12g) of [[Carbon]]. | : [[Mole]]s are based on the number of [[Carbon]] [[atom]]s in exactly 0.012kg (12g) of [[Carbon]]. | ||
: [[Mole]]s are used to give a conversion between the number of [[atom]]s in a [[substance]] and useful quantities for [[Chemical Reaction|chemical reaction]]s. It would not be useful to talk about 1,000,000,000 [[atom]]s in a [[Chemical Reaction|chemical reaction]] because that would be such a small amount of the [[chemical]] (0.0000000000000017g). | : [[Mole]]s are used to give a conversion between the number of [[atom]]s in a [[substance]] and useful quantities for [[Chemical Reaction|chemical reaction]]s. It would not be useful to talk about 1,000,000,000 [[atom]]s in a [[Chemical Reaction|chemical reaction]] because that would be such a small amount of the [[chemical]] (0.0000000000000017g). | ||
− | : The [[Relative Atomic Mass|relative atomic mass]] of an [[element]] is the [[mass]] of 1 [[mole]] or the [[mass]] of [[ | + | : The [[Relative Atomic Mass|relative atomic mass]] of an [[element]] is the [[mass]] of 1 [[mole]] or the [[mass]] of [[Avogadro Constant|6.02x10<sup>23</sup>]] [[atom]]s. So 1g of [[Hydrogen]] is 1 [[mole]] and contains [[Avogadro Constant|6.02x10<sup>23</sup>]] [[atom]]s. 235g of [[Uranium-235]] is 1 [[mole]] and contains [[Avogadro Constant|6.02x10<sup>23</sup>]] [[atom]]s. |
===Equation=== | ===Equation=== |
Revision as of 11:44, 29 October 2019
Contents
Key Stage 4
Meaning
A mole is an SI Unit used to show 6.02x1023 particles of a chemical.
About Moles
- Moles are based on the number of Carbon atoms in exactly 0.012kg (12g) of Carbon.
- Moles are used to give a conversion between the number of atoms in a substance and useful quantities for chemical reactions. It would not be useful to talk about 1,000,000,000 atoms in a chemical reaction because that would be such a small amount of the chemical (0.0000000000000017g).
- The relative atomic mass of an element is the mass of 1 mole or the mass of 6.02x1023 atoms. So 1g of Hydrogen is 1 mole and contains 6.02x1023 atoms. 235g of Uranium-235 is 1 mole and contains 6.02x1023 atoms.
Equation
Number of Moles of an Element = (Mass of Element)/(Relative Atomic Mass of Element)
Number of Moles = \({\frac{m}{A_r}}\)
Where:
m = The mass of element being used.
Ar = The Relative Atomic Mass of the Element
Number of Moles of a Compound = (Mass of compound)/(Relative Formula Mass of compound)
Number of Moles = \({\frac{m}{M_r}}\)
Where:
m = The mass of compound being used.
Mr = The Relative Formula Mass of the compound
Calculating Moles
Calculating Moles from Masses
The Periodic Table is needed to for mole calculations in order to find the Relative Atomic Masses of the elements.
Calculate the number of moles in 36g of Carbon | Calculate the number of moles in 2g of Oxygen | Calculate the number of moles in 47g of Uranium-235 |
Relative Atomic Mass of Carbon = 12g No. Moles = \({\frac{m}{A_r}}\) No. Moles = \({\frac{36}{12}}\) No. Moles = 3mol |
Relative Atomic Mass of Oxygen = 16g No. Moles = \({\frac{m}{A_r}}\) No. Moles = \({\frac{2}{16}}\) No. Moles = 0.125mol |
Relative Atomic Mass of Uranium-235 = 235g No. Moles = \({\frac{m}{A_r}}\) No. Moles = \({\frac{47}{235}}\) No. Moles = 0.2mol |
Calculate the number of moles in 32g of Methane | Calculate the number of moles in 22g of Carbon Dioxide | Calculate the number of moles in 115g of Ethanol |
Chemical Formula of Methane = CH4 Relative Atomic Mass of Carbon = 12g Relative Atomic Mass of Hydrogen = 1g Relative Formula Mass of CH4 = 12 + 1 x 4 Relative Formula Mass of CH4 = 16 No. Moles = \({\frac{m}{M_r}}\) No. Moles = \({\frac{32}{16}}\) No. Moles = 2mol |
Chemical Formula of Carbon Dioxide = CO2 Relative Atomic Mass of Carbon = 12g Relative Atomic Mass of Oxygen = 16g Relative Formula Mass of CH4 = 12 + 16 x 2 Relative Formula Mass of CH4 = 44g No. Moles = \({\frac{m}{M_r}}\) No. Moles = \({\frac{22}{44}}\) No. Moles = 0.5mol |
Chemical Formula of Ethanol = C2H5OH Relative Atomic Mass of Carbon = 12g Relative Atomic Mass of Hydrogen = 1g Relative Atomic Mass of Oxygen = 16g Relative Formula Mass of CH4 = 12x2 + 1x6 + 16 Relative Formula Mass of CH4 = 46g No. Moles = \({\frac{m}{M_r}}\) No. Moles = \({\frac{115}{46}}\) No. Moles = 2.5mol |