Difference between revisions of "Electrical Current"
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: Conventional '''Current''' flows from [[positive]] to [[negative]]. This is because [[electricity]] was discovered before [[scientist]]s knew about [[electron]]s. | : Conventional '''Current''' flows from [[positive]] to [[negative]]. This is because [[electricity]] was discovered before [[scientist]]s knew about [[electron]]s. | ||
: In a [[salt]] [[solution]] '''current''' is the flow of both [[positive]] and [[negative]] [[ion]]s. | : In a [[salt]] [[solution]] '''current''' is the flow of both [[positive]] and [[negative]] [[ion]]s. | ||
+ | |||
+ | ==Key Stage 4== | ||
+ | ===Meaning=== | ||
+ | '''Electrical current''' is the [[rate]] of flow of [[Electrical Charge|charge]]. | ||
+ | |||
+ | ===About Electrical Current=== | ||
+ | : '''Current''' is [[measure]]d using an [[Ammeter]]. | ||
+ | : The [[SI Unit]]s of '''current''' are [[Amp|amperes]], which are also called [[amp]]s ([[A]]). | ||
+ | : A '''current''' in a [[wire]] is a flow of [[electron]]s which are [[negative]]ly [[Electrical Charge|charge]]d [[particle]]s. | ||
+ | : Conventional '''Current''' flows from [[positive]] to [[negative]]. This is because [[electricity]] was discovered before [[scientist]]s knew about [[electron]]s. | ||
+ | : In a [[salt]] [[solution]] '''current''' is the flow of both [[positive]] and [[negative]] [[ion]]s. | ||
+ | : In a [[Series Circuit|series circuit]] the '''current''' is the same everywhere in the [[circuit]]. | ||
+ | : In a [[Parallel Circuit|parallel circuit]] the '''current''' splits at a [[junction]]. | ||
+ | |||
+ | ===Equation=== | ||
+ | '''Current''' = (Charge)/(time) | ||
+ | |||
+ | <math>I=\frac{Q}{t}</math> | ||
+ | |||
+ | Where: | ||
+ | |||
+ | <math>I</math> = The '''electrical current''' | ||
+ | |||
+ | <math>Q</math> = The amount of [[Electrical Charge|charge]] flowing past a point. | ||
+ | |||
+ | <math>t</math> = The time taken for the [[Electrical Charge|charge]] to flow. | ||
+ | |||
+ | : This can give the definition "Current (I) is the (=) amount of [[Electrical Charge|charge]] flowing past a point (Q) per (÷) unit time (t). | ||
+ | |||
+ | ===Example Calculations=== | ||
+ | {| class="wikitable" | ||
+ | | style="height:20px; width:300px; text-align:center;" |A charge of 15 Coulombs passes through a point in a circuit ever 0.5 seconds. Calculate the current flowing past this point correct to two [[Significant Figures|significant figures]]. | ||
+ | | style="height:20px; width:300px; text-align:center;" |A capacitor stores a charge of 10C. It discharges in 12ms. Calculate the current flowing out of the capacitor correct to two [[Significant Figures|significant figures]]. | ||
+ | |- | ||
+ | | style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities''' | ||
+ | |||
+ | Q = 15C | ||
+ | |||
+ | t = 0.5s | ||
+ | | style="height:20px; width:300px; text-align:left;" |'''1. State the known quantities''' | ||
+ | |||
+ | Q = 10C | ||
+ | |||
+ | t = 12ms = 12x10<sup>-3</sup>s | ||
+ | |- | ||
+ | | style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' | ||
+ | |||
+ | <math>I=\frac{Q}{t}</math> | ||
+ | |||
+ | <math>I=\frac{15}{0.5}</math> | ||
+ | |||
+ | <math>I=30A</math> | ||
+ | |||
+ | | style="height:20px; width:300px; text-align:left;" |'''2. [[Substitute (Maths)|Substitute]] the numbers into the [[equation]] and [[Solve (Maths)|solve]].''' | ||
+ | |||
+ | <math>I=\frac{Q}{t}</math> | ||
+ | |||
+ | <math>I=\frac{10}{12 \times 10^{-3}}</math> | ||
+ | |||
+ | <math>I=833.3A</math> | ||
+ | |||
+ | <math>I\approx830A</math> | ||
+ | |} |
Revision as of 19:26, 24 February 2019
Contents
Key Stage 2
Meaning
Electrical Current is the amount of electricity flowing through a wire.
About Electrical Current
- The bigger the electrical current the brighter a bulb and the louder a buzzer.
- If an electrical current goes through an animal it is called an electrical shock.
Key Stage 3
Meaning
An electrical current is a flow of charge.
About Electrical Current
- Current is measured using an Ammeter.
- The units of current are amperes, which are also called amps (A).
- A current in a wire is a flow of electrons which are negatively charged particles.
- Conventional Current flows from positive to negative. This is because electricity was discovered before scientists knew about electrons.
- In a salt solution current is the flow of both positive and negative ions.
Key Stage 4
Meaning
Electrical current is the rate of flow of charge.
About Electrical Current
- Current is measured using an Ammeter.
- The SI Units of current are amperes, which are also called amps (A).
- A current in a wire is a flow of electrons which are negatively charged particles.
- Conventional Current flows from positive to negative. This is because electricity was discovered before scientists knew about electrons.
- In a salt solution current is the flow of both positive and negative ions.
- In a series circuit the current is the same everywhere in the circuit.
- In a parallel circuit the current splits at a junction.
Equation
Current = (Charge)/(time)
\(I=\frac{Q}{t}\)
Where\[I\] = The electrical current
\(Q\) = The amount of charge flowing past a point.
\(t\) = The time taken for the charge to flow.
- This can give the definition "Current (I) is the (=) amount of charge flowing past a point (Q) per (÷) unit time (t).
Example Calculations
A charge of 15 Coulombs passes through a point in a circuit ever 0.5 seconds. Calculate the current flowing past this point correct to two significant figures. | A capacitor stores a charge of 10C. It discharges in 12ms. Calculate the current flowing out of the capacitor correct to two significant figures. |
1. State the known quantities
Q = 15C t = 0.5s |
1. State the known quantities
Q = 10C t = 12ms = 12x10-3s |
2. Substitute the numbers into the equation and solve.
\(I=\frac{Q}{t}\) \(I=\frac{15}{0.5}\) \(I=30A\) |
2. Substitute the numbers into the equation and solve.
\(I=\frac{Q}{t}\) \(I=\frac{10}{12 \times 10^{-3}}\) \(I=833.3A\) \(I\approx830A\) |