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'''Balanced Forces''' are [[Forces]] that are the same strength but acting in opposite directions.
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==Key Stage 3==
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===Meaning===
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'''Balanced Forces''' are [[Force|forces]] that are the same strength but acting in opposite directions.
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===About Balanced Forces===
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: When [[force]]s are '''balanced''' an [[object]] will travel at a constant [[speed]] and in the same direction.
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{| class="wikitable"
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|-
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|[[File:BalancedForces1.png|center|150px]]
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|[[File:BalancedForces2.png|center|200px]]
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|[[File:BalancedForces3.png|center|200px]]
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|-
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| style="height:20px; width:200px; text-align:center;" |The 7[[Newton|N]] up is '''balanced''' by the 7[[Newton|N]] down.
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| style="height:20px; width:200px; text-align:center;" |The 4[[Newton|N]] left is '''balanced''' by the 4[[Newton|N]] right.
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| style="height:20px; width:200px; text-align:center;" |The 6[[Newton|N]] up is '''balanced''' by the 6[[Newton|N]] down and the 5[[Newton|N]] left is '''balanced''' by the 5[[Newton|N]] right.
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|}
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==Key Stage 4==
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===Meaning===
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'''Balanced forces''' are [[force]] [[vector]]s which add together to make 0N [[Resultant Force|resultant force]].
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===About Balanced Forces===
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: When [[force]]s on an [[object]] are '''balanced''' there is no [[acceleration]] (change speed or direction).
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: '''Balanced forces''' are related to [[Newton's First Law]] of motion:
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:: An [[object]] in motion will tend to stay in motion in a straight line and an [[object]] at [[rest]] will tend to stay at [[rest]] unless an [[Unbalanced Forces|unbalanced force]] acts upon it.
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: If the [[Resultant Force|resultant force]] on an [[object]] is zero, then the [[force]]s are '''balanced'''.
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===Examples===
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{| class="wikitable"
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|-
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|[[File:BalancedForces4.png|center|200px]]
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|[[File:BalancedForces5.png|center|200px]]
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|[[File:BalancedForces6.png|center|200px]]
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|-
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| style="height:20px; width:200px; text-align:center;" |
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<math>F_R = F_{up} - F_{down}</math>
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<math>F_R = 3 - 3</math>
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<math>F_R = 0N</math>
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The [[force]]s are '''balanced'''.
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| style="height:20px; width:200px; text-align:center;" |
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<math>F_R = F_{right} - F_{left}</math>
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<math>F_R = 80 - 80</math>
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<math>F_R = 0N</math>
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The [[force]]s are '''balanced'''.
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| style="height:20px; width:200px; text-align:center;" |
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<math>F_{Horiztonal} = F_{right} - F_{left}</math>
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<math>F_{Horiztonal} = 40 - 40</math>
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<math>F_{Horiztonal} = 0N</math>
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<math>F_{Vertical} = F_{up} - F_{down}</math>
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<math>F_{Vertical} = 38 - 38</math>
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<math>F_{Vertical} = 0N</math>
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The [[force]]s are '''balanced'''.
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|}
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{| class="wikitable"
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|-
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|[[File:BalancedForces7.png|center|600px]]
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|-
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| style="height:20px; width:200px; text-align:center;" |
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Whether these [[force]]s are '''balanced''' can be found by [[Resolving Forces|resolving]] the blue [[force]] [[vector]]s into the [[horizontal]]. See [[Resolving Forces]].
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<math>F_{right} = 50\cos37 + 50\cos37</math>
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<math>F_{right} = 79.86N</math>
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Since the [[angle]] in the question is given to two [[Significant Figures|significant figures]] the answer should also be quoted to two [[Significant Figures|significant figures]].
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<math>F_{right} \approx 80N</math>
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<math>F_R = F_{right} - F_{left}</math>
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<math>F_R = 80 - 80</math>
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<math>F_R = 0N</math>
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|}
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===References===
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====AQA====
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:[https://www.amazon.co.uk/gp/product/019835939X/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=019835939X&linkCode=as2&tag=nrjc-21&linkId=57e96876985fc39b1a3d8a3e3dc238b6 ''Balanced forces, pages 114-133, GCSE Physics; Third Edition, Oxford University Press, AQA '']
 +
:[https://www.amazon.co.uk/gp/product/1782946403/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782946403&linkCode=as2&tag=nrjc-21&linkId=32a0abb60dff015b15b50e9b1d7b4644 ''Balanced forces, pages 133, 170, GCSE Combined Science Trilogy; Physics, CGP, AQA '']
 +
:[https://www.amazon.co.uk/gp/product/1782945970/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1782945970&linkCode=as2&tag=nrjc-21&linkId=a120d24dcc7cc7a58192069a3aafc1d2 ''Balanced forces, pages 153, 166, 202, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA '']
 +
:[https://www.amazon.co.uk/gp/product/0008158770/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=0008158770&linkCode=as2&tag=nrjc-21&linkId=ec31595e720e1529e49876c3866fff6e ''Balanced forces, pages 154-6, GCSE Physics; Student Book, Collins, AQA '']
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====Edexcel====
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:[https://www.amazon.co.uk/gp/product/1292120223/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120223&linkCode=as2&tag=nrjc-21&linkId=068ecf40278c32406a7f1c6e66751417 ''Balanced forces, page 13, GCSE Physics, Pearson Edexcel '']
 +
:[https://www.amazon.co.uk/gp/product/1292120193/ref=as_li_tl?ie=UTF8&camp=1634&creative=6738&creativeASIN=1292120193&linkCode=as2&tag=nrjc-21&linkId=572df39392fb4200db8391d98ae6314e ''Balanced forces, page 297, GCSE Combined Science, Pearson Edexcel '']

Latest revision as of 14:13, 2 November 2019

Key Stage 3

Meaning

Balanced Forces are forces that are the same strength but acting in opposite directions.

About Balanced Forces

When forces are balanced an object will travel at a constant speed and in the same direction.
BalancedForces1.png
BalancedForces2.png
BalancedForces3.png
The 7N up is balanced by the 7N down. The 4N left is balanced by the 4N right. The 6N up is balanced by the 6N down and the 5N left is balanced by the 5N right.

Key Stage 4

Meaning

Balanced forces are force vectors which add together to make 0N resultant force.

About Balanced Forces

When forces on an object are balanced there is no acceleration (change speed or direction).
Balanced forces are related to Newton's First Law of motion:
An object in motion will tend to stay in motion in a straight line and an object at rest will tend to stay at rest unless an unbalanced force acts upon it.
If the resultant force on an object is zero, then the forces are balanced.

Examples

BalancedForces4.png
BalancedForces5.png
BalancedForces6.png

\(F_R = F_{up} - F_{down}\)

\(F_R = 3 - 3\)

\(F_R = 0N\)

The forces are balanced.

\(F_R = F_{right} - F_{left}\)

\(F_R = 80 - 80\)

\(F_R = 0N\)

The forces are balanced.

\(F_{Horiztonal} = F_{right} - F_{left}\)

\(F_{Horiztonal} = 40 - 40\)

\(F_{Horiztonal} = 0N\)

\(F_{Vertical} = F_{up} - F_{down}\)

\(F_{Vertical} = 38 - 38\)

\(F_{Vertical} = 0N\)

The forces are balanced.

BalancedForces7.png

Whether these forces are balanced can be found by resolving the blue force vectors into the horizontal. See Resolving Forces.

\(F_{right} = 50\cos37 + 50\cos37\)

\(F_{right} = 79.86N\)

Since the angle in the question is given to two significant figures the answer should also be quoted to two significant figures.

\(F_{right} \approx 80N\)

\(F_R = F_{right} - F_{left}\)

\(F_R = 80 - 80\)

\(F_R = 0N\)

References

AQA

Balanced forces, pages 114-133, GCSE Physics; Third Edition, Oxford University Press, AQA
Balanced forces, pages 133, 170, GCSE Combined Science Trilogy; Physics, CGP, AQA
Balanced forces, pages 153, 166, 202, GCSE Physics; The Complete 9-1 Course for AQA, CGP, AQA
Balanced forces, pages 154-6, GCSE Physics; Student Book, Collins, AQA

Edexcel

Balanced forces, page 13, GCSE Physics, Pearson Edexcel
Balanced forces, page 297, GCSE Combined Science, Pearson Edexcel
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