Difference between revisions of "SUVAT"
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===Example Calculations=== | ===Example Calculations=== | ||
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| style="height:20px; width:200px; text-align:center;" |A [[wave]] travels 1000m in a time of 12.5s. Calculate the [[magnitude]] of the [[velocity]] of the [[wave]] correct to two [[Significant Figures|significant figures]]. | | style="height:20px; width:200px; text-align:center;" |A [[wave]] travels 1000m in a time of 12.5s. Calculate the [[magnitude]] of the [[velocity]] of the [[wave]] correct to two [[Significant Figures|significant figures]]. | ||
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<math>v = 15,000,000m/s</math> | <math>v = 15,000,000m/s</math> | ||
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| + | ====Using a, v, u and t==== | ||
| + | ====Using v, u a and s==== | ||
Revision as of 15:44, 13 February 2019
Contents
Key Stage 4
Meaning
A suvat is an equation of motion for an object.
About suvat Equations
- suvat equations can be used to find one of these variables:
- Displacement (s) - How far an object is from its starting position.
- Initial Velocity (u) - The velocity of an object at the start.
- Final Velocity (v) - The velocity of an object at the end.
- Acceleration (a) - The rate of change of velocity.
- Time (t) - The time taken between to points on a journey.
Equations
\(v=\frac{s}{t}\)
\(a=\frac{v-u}{t}\)
\(v^2=u^2 + 2as\)
Example Calculations
Using v, s and t
| A wave travels 1000m in a time of 12.5s. Calculate the magnitude of the velocity of the wave correct to two significant figures. | The Moon is approximately 390,000km away from the Earth. It takes a Radio Wave 1.3 seconds to travel that distance. Calculate the magnitude of the velocity of the Radio Wave correct to two significant figures. | An alpha particle can travels around 6cm from a source taking 4.0ns before colliding with an air molecule. Calculate the magnitude of its velocity on this journey correct to two significant figures. |
| 1. State the known quantities
s = 1000m t = 12.5s |
1. State the known quantities
s = 390,000km = 390,000,000m t = 1.3s |
1. State the known quantities
s = 6cm = 0.06m t = 4.0ns = 4.0 x 10-9m |
| 2. Substitute the numbers into the equation and solve.
\(v = \frac{s}{t}\) \(v = \frac{1000}{12.5}\) \(v = 80m/s\) |
2. Substitute the numbers into the equation and solve.
\(v = \frac{s}{t}\) \(v = \frac{390000000}{1.3}\) \(v = 300,000,000m/s\) |
2. Substitute the numbers into the equation and solve.
\(v = \frac{s}{t}\) \(v = \frac{0.06}{4.0 \times 10^{-9}}\) \(v = 15,000,000m/s\) |